
Oxygen boils at $-{{183}^{\circ }}C$ . This temperature in Fahrenheit scale is approximately:
\[\begin{align}
& A){{215}^{\circ }}F \\
& B)-{{297.4}^{\circ }}F \\
& C){{329}^{\circ }}F \\
& D)361{{~}^{\circ }}F \\
\end{align}\]
Answer
523.5k+ views
Hint: We used a formula to relate the temperatures of Fahrenheit scale to that of the absolute scale. We can consider two different sets of temperatures that provide us with two equations. A temperature scale is defined by choosing two fixed points whose values are easily reproduced. In the case of the Celsius scale, the lower point is the melting point of pure ice at normal atmospheric pressure and the upper fixed point is the boiling point of pure water at normal atmospheric pressure.
Formula used: ${{T}_{f}}={{T}_{C}}\times \dfrac{9}{5}+32$
Complete step by step answer:
We know that a temperature scale is a unit of measurement to measure the temperature. Usually, scales of temperature are developed by first fixing points. The temperature values of these two limits must be easily reproducible by some natural phenomenon. Then the scale is calibrated by making equal divisions between these two limits. Let us consider ${{T}_{f}}$ to be the temperature of water in Fahrenheit scale and ${{T}_{C}}$ to be the temperature on the celsius.
${{T}_{C}}$ given to us is $-{{183}^{\circ }}C$.
Now, we can relate both the scales together by,
$\begin{align}
& {{T}_{f}}={{T}_{C}}\times \dfrac{9}{5}+32 \\
& \Rightarrow {{T}_{f}}=-183\times \dfrac{9}{5}+32={{361.4}^{\circ }}F \\
\end{align}$
So, the given temperature in Fahrenheit scale is found to be ${{361.4}^{\circ }}F$.
So, the correct answer is “Option D”.
Note: We need to analyze the requirement and the data that the question provides. In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases of that substance i.e., solid, liquid and gas coexist in thermodynamic equilibrium. In the phase diagram, the point where the sublimation curve, fusion curve and the vaporization curve meet, its temperature and pressure is known as the triple point. For example, the triple point of mercury occurs at a pressure of 0.2 mPa and at a temperature of $-{{38.83440}^{\circ }}C$ .
Formula used: ${{T}_{f}}={{T}_{C}}\times \dfrac{9}{5}+32$
Complete step by step answer:
We know that a temperature scale is a unit of measurement to measure the temperature. Usually, scales of temperature are developed by first fixing points. The temperature values of these two limits must be easily reproducible by some natural phenomenon. Then the scale is calibrated by making equal divisions between these two limits. Let us consider ${{T}_{f}}$ to be the temperature of water in Fahrenheit scale and ${{T}_{C}}$ to be the temperature on the celsius.
${{T}_{C}}$ given to us is $-{{183}^{\circ }}C$.
Now, we can relate both the scales together by,
$\begin{align}
& {{T}_{f}}={{T}_{C}}\times \dfrac{9}{5}+32 \\
& \Rightarrow {{T}_{f}}=-183\times \dfrac{9}{5}+32={{361.4}^{\circ }}F \\
\end{align}$
So, the given temperature in Fahrenheit scale is found to be ${{361.4}^{\circ }}F$.
So, the correct answer is “Option D”.
Note: We need to analyze the requirement and the data that the question provides. In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases of that substance i.e., solid, liquid and gas coexist in thermodynamic equilibrium. In the phase diagram, the point where the sublimation curve, fusion curve and the vaporization curve meet, its temperature and pressure is known as the triple point. For example, the triple point of mercury occurs at a pressure of 0.2 mPa and at a temperature of $-{{38.83440}^{\circ }}C$ .
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE
