What is the oxidation number of Mn in \[\text{KMn}{{\text{O}}_{4}},\text{ }{{\text{K}}_{2}}\text{Mn}{{\text{O}}_{4}},\text{ MnS}{{\text{O}}_{4}},\text{ Mn}{{\text{O}}_{2}}\text{ and M}{{\text{n}}_{3}}{{\text{O}}_{4}}\] respectively:
A. +7, +6, +2, +4, \[+\dfrac{8}{3}\]
B. +4, +6, +2, +4, \[+\dfrac{8}{3}\]
C. +7, +6, +2, +3, \[+\dfrac{8}{3}\]
D. None of these
Answer
545.6k+ views
Hint: Oxidation number is also known as oxidation state. It is a number which tells us how many electrons have been lost or gained by an atom. Single elements have the oxidation state of zero always in every reaction.
Complete step by step solution:
-To determine the oxidation state of an atom, we will consider it as 'X'.
- So to calculate the oxidation state of manganese in \[\text{KMn}{{\text{O}}_{4}}\], we will consider the oxidation state of manganese as 'X'.
-We know that the oxidation state of potassium and oxygen are +1 & -2.
-So, the equation will become:
$\begin{align}
& \text{+1 + x - 8 = 0} \\
& \text{x = +7} \\
\end{align}$
-Hence, the oxidation of Mn is +7.
-Similarly, the oxidation state of Mn in ${{\text{K}}_{2}}\text{Mn}{{\text{O}}_{4}}$ will be
$\begin{align}
& +2\text{ + x - 8 = 0} \\
& \text{x = +6} \\
\end{align}$
-So, the oxidation state of Mn is +6
-Now, the oxidation state of Mn in $\text{MnS}{{\text{O}}_{4}}$ will be
$\begin{align}
& \text{x + 6 - 8 = 0} \\
& \text{x - 2 = 0} \\
& \text{x = +2} \\
\end{align}$
-We know that the oxidation state of sulphur in sulphate ion is +6 so we have put +6 as an oxidation state of sulphur.
-So, the oxidation state of Mn is +2.
- Now, we will calculate the oxidation state of Mn in $\text{Mn}{{\text{O}}_{2}}$
$\begin{align}
& \text{x - 4 = 0} \\
& \text{x = +4} \\
\end{align}$
-So, the oxidation state of Mn is +2.
-Now, we will calculate the oxidation state of Mn in \[\text{M}{{\text{n}}_{3}}{{\text{O}}_{4}}\]
\[\begin{align}
& 3\text{x - 8 = 0} \\
& \text{x = +}\dfrac{8}{3} \\
\end{align}\]
-So, the oxidation state of Mn is + 8/3.
Therefore, option A. is the correct answer.
Note: Potassium permanganate comes under the category of strong oxidising agents. Sulphur has many oxidation states such as -2, 0, +2, +4, +6 and it depends on the bonding of the sulphur with other atoms. Like in Manganese sulfate sulphur has an oxidation state of +6.
Complete step by step solution:
-To determine the oxidation state of an atom, we will consider it as 'X'.
- So to calculate the oxidation state of manganese in \[\text{KMn}{{\text{O}}_{4}}\], we will consider the oxidation state of manganese as 'X'.
-We know that the oxidation state of potassium and oxygen are +1 & -2.
-So, the equation will become:
$\begin{align}
& \text{+1 + x - 8 = 0} \\
& \text{x = +7} \\
\end{align}$
-Hence, the oxidation of Mn is +7.
-Similarly, the oxidation state of Mn in ${{\text{K}}_{2}}\text{Mn}{{\text{O}}_{4}}$ will be
$\begin{align}
& +2\text{ + x - 8 = 0} \\
& \text{x = +6} \\
\end{align}$
-So, the oxidation state of Mn is +6
-Now, the oxidation state of Mn in $\text{MnS}{{\text{O}}_{4}}$ will be
$\begin{align}
& \text{x + 6 - 8 = 0} \\
& \text{x - 2 = 0} \\
& \text{x = +2} \\
\end{align}$
-We know that the oxidation state of sulphur in sulphate ion is +6 so we have put +6 as an oxidation state of sulphur.
-So, the oxidation state of Mn is +2.
- Now, we will calculate the oxidation state of Mn in $\text{Mn}{{\text{O}}_{2}}$
$\begin{align}
& \text{x - 4 = 0} \\
& \text{x = +4} \\
\end{align}$
-So, the oxidation state of Mn is +2.
-Now, we will calculate the oxidation state of Mn in \[\text{M}{{\text{n}}_{3}}{{\text{O}}_{4}}\]
\[\begin{align}
& 3\text{x - 8 = 0} \\
& \text{x = +}\dfrac{8}{3} \\
\end{align}\]
-So, the oxidation state of Mn is + 8/3.
Therefore, option A. is the correct answer.
Note: Potassium permanganate comes under the category of strong oxidising agents. Sulphur has many oxidation states such as -2, 0, +2, +4, +6 and it depends on the bonding of the sulphur with other atoms. Like in Manganese sulfate sulphur has an oxidation state of +6.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

