
Oxalic acid ${H_2}{C_2}{O_4}$ is present in many plants and vegetables. If 24.0 mL of 0.01M $KMn{O_4}$ solution is needed to titrate 1.0 g of ${H_2}{C_2}{O_4}$ to equivalence point, the mass percentage (as nearest integer) of ${H_2}{C_2}{O_4}$ in the sample is:
Answer
558.6k+ views
Hint: Equivalence point: point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution. At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water.
Complete Step by step answer:Mass percentage is one way of representing the concentration of an element in a compound or a component in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%.
Number of moles $KMn{O_4}$ = $\dfrac{{volume}}{{1000}} \times molarity$
Here, we are given with volume =24.0mL and molarity =0.01.
Number of moles $KMn{O_4}$= $\dfrac{{24.0}}{{1000}} \times 0.01 = 0.00024mol.$
2 moles of $KMn{O_4}$ = 5 moles of ${H_2}{C_2}{O_4}$
So 1 moles of$KMn{O_4}$ =$\dfrac{5}{2}$ moles of ${H_2}{C_2}{O_4}$and therefore 0.00024 moles of$KMn{O_4}$ = $\dfrac{5}{2} \times 0.00024 = 0.0006mol$ of ${H_2}{C_2}{O_4}$.
Number of moles of ${H_2}{C_2}{O_4}$ =$\dfrac{5}{2} \times 0.00024 = 0.0006mol$
Mass of ${H_2}{C_2}{O_4}$ = $mass = molar\;mass \times moles$ (Molar mass of oxalic acid = 90 g/mol. And
moles = 0.0006.) $mass = 0.0006 \times 90 = 0.054g$.
Mass percent is the mass of the element or solute divided by the mass of the compound or solute. The result is multiplied by 100 to give a percent.
The formula for the amount of an element in a compound is:
mass percent = (mass of element in 1 mole of compound / mass of 1 mole of compound) x 100
Mass percentage of ${H_2}{C_2}{O_4}$= $\dfrac{{0.054}}{1} \times 100 = 5.4\% $
The nearest integer is 5.
Note: The main difference between equivalence and endpoint is that the equivalence point is a point where the chemical reaction comes to an end while the endpoint is the point where the color change occurs in a system.
Complete Step by step answer:Mass percentage is one way of representing the concentration of an element in a compound or a component in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%.
Number of moles $KMn{O_4}$ = $\dfrac{{volume}}{{1000}} \times molarity$
Here, we are given with volume =24.0mL and molarity =0.01.
Number of moles $KMn{O_4}$= $\dfrac{{24.0}}{{1000}} \times 0.01 = 0.00024mol.$
2 moles of $KMn{O_4}$ = 5 moles of ${H_2}{C_2}{O_4}$
So 1 moles of$KMn{O_4}$ =$\dfrac{5}{2}$ moles of ${H_2}{C_2}{O_4}$and therefore 0.00024 moles of$KMn{O_4}$ = $\dfrac{5}{2} \times 0.00024 = 0.0006mol$ of ${H_2}{C_2}{O_4}$.
Number of moles of ${H_2}{C_2}{O_4}$ =$\dfrac{5}{2} \times 0.00024 = 0.0006mol$
Mass of ${H_2}{C_2}{O_4}$ = $mass = molar\;mass \times moles$ (Molar mass of oxalic acid = 90 g/mol. And
moles = 0.0006.) $mass = 0.0006 \times 90 = 0.054g$.
Mass percent is the mass of the element or solute divided by the mass of the compound or solute. The result is multiplied by 100 to give a percent.
The formula for the amount of an element in a compound is:
mass percent = (mass of element in 1 mole of compound / mass of 1 mole of compound) x 100
Mass percentage of ${H_2}{C_2}{O_4}$= $\dfrac{{0.054}}{1} \times 100 = 5.4\% $
The nearest integer is 5.
Note: The main difference between equivalence and endpoint is that the equivalence point is a point where the chemical reaction comes to an end while the endpoint is the point where the color change occurs in a system.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

