Question

What about the concentration of acids in both reactions?

Answer 1

Hint: In this question, we are asked to find out what is the effect of the shape or size of particles of a reactant on the reaction and thus the concentration of the solution. We are given calcium carbonate and dilute hydrochloric acid and are asked to find out the concentration of the resulting solution in both cases.

Complete answer: Here we are given a marble piece and powdered marble piece in equal amounts of diluted hydrochloric acid in separate beakers. We know that marble pieces are chemically Calcium carbonate and they can react with Hydrochloric acid to produce calcium chloride and carbon dioxide gas. The carbon dioxide gas will escape leaving us with a solution of calcium chloride. The reaction is as shown below:
\[ CaC{O_3}\; + {\text{ }}2HCl{\text{ }} \to {\text{ }}CaC{l_2}\; + {\text{ }}{H_2}O{\text{ }} + {\text{ }}C{O_2}\]
We know that the concentration of any solution will only depend upon the amount of solute and solvent taken. Even if the taken solute is in powdered form or in a bulk solid form, as long as the amount of calcium carbonate in the sample doesn’t change there will not be any change in the concentration of the solution.
Thus we can say that both the solutions will have the same concentration.

Note:
It is important to note that when reacting together it is easier for the powdered form of any substance to react than its bulk solid form. This is because the surface area of the powdered form will be very large compared to the marble piece and therefore the reaction can occur faster. The concentration of the solution will be the same in both the beakers even though the one will take more time to reach that concentration.