
Out of 1M glucose and 2M glucose has higher boiling point?
(A) True
(B) False
Answer
554.7k+ views
Hint: To answer this question we should know the definition of boiling point. In this question the quantity should be considered, so firstly we should focus on what 1M or 2M of glucose means. Understanding these two points we can answer this question within no time.
Complete answer:
Boiling point is the temperature at which the pressure exerted on the liquid surface from surroundings is equal to the pressure exerted by the vapour of the liquid.
Firstly it is more important to know what do you mean by 1M means 1 molar solution or molarity.
Formula to calculate molarity:
Molarity = $\dfrac{moles\text{ }of\text{ }solute~}{kilogram\text{ }of\text{ }solvent}$
1 mole of glucose is dissolved into 1litre of water to make 1M glucose. Similarly, To make 2M glucose 2moles of glucose is dissolved in 1L.
Boiling point can be also considered as the colligative property. We know that colligative property directly depends on the number or amount of constituent atoms.
In this case we can say that 1M of glucose will contain less number of constituent atoms or molecules than that of 2M of glucose. Breaking all the bonds in glucose molecules present in 1M glucose in comparison to 2M glucose. 2M glucose has a higher boiling point than 1M glucose.
Thus, option A is the correct answer.
Note:
We can account for the boiling point of given compounds in many aspects but in this question we account for the boiling point of a given compound by considering it as a colligative property, because we are asked to compare the boiling point of 1M and 2M glucose which is some quantity.
Complete answer:
Boiling point is the temperature at which the pressure exerted on the liquid surface from surroundings is equal to the pressure exerted by the vapour of the liquid.
Firstly it is more important to know what do you mean by 1M means 1 molar solution or molarity.
Formula to calculate molarity:
Molarity = $\dfrac{moles\text{ }of\text{ }solute~}{kilogram\text{ }of\text{ }solvent}$
1 mole of glucose is dissolved into 1litre of water to make 1M glucose. Similarly, To make 2M glucose 2moles of glucose is dissolved in 1L.
Boiling point can be also considered as the colligative property. We know that colligative property directly depends on the number or amount of constituent atoms.
In this case we can say that 1M of glucose will contain less number of constituent atoms or molecules than that of 2M of glucose. Breaking all the bonds in glucose molecules present in 1M glucose in comparison to 2M glucose. 2M glucose has a higher boiling point than 1M glucose.
Thus, option A is the correct answer.
Note:
We can account for the boiling point of given compounds in many aspects but in this question we account for the boiling point of a given compound by considering it as a colligative property, because we are asked to compare the boiling point of 1M and 2M glucose which is some quantity.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

