
One-half of the number is eight less than the number. What if the number?
Answer
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Hint: We will convert the given information mathematically, which is the algebraic expansion in mathematics is the expression that is made up of the variables and numbers along with the operations. An expression is a group of terms. After converting it was easy to solve the given problem.
Complete step-by-step solution:
Since given that we have the information of One-second of the number is eight less than the number.
Let us fix the unknown number that we need to find as $x$
Thus, one-second of the number means $\dfrac{1}{2}x$ also given that the eight is less than the number, which is expressed as mathematically as $x - 8$.
Hence the One-second of the number is eight less than the number expressed as $\dfrac{1}{2}x = x - 8$
Now we will multiple both terms with the number $2$ then we get $2 \times \dfrac{1}{2}x = 2(x - 8)$
By the division we have $2 \times \dfrac{1}{2}x = 2(x - 8) \Rightarrow x = 2x - 16$
Taking the variables on the left side and numbers on the right side we get $x - 2x = - 16$ and by subtraction, we get $ - x = - 16$ and again by division we get $x = 16$
Hence, we found the unknown number as $16$.
Note: The four major operations in mathematics are addition, subtraction, multiplication, and division.
The addition is the summing of two or more than two numbers, or values, or variables, and in addition if we sum the two or more numbers a new frame of the number will be found.
Subtraction is the minus of two or more than two numbers or values example $2 - 3 = - 1$ (larger number signs stays constant)
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$is called the multiplicand and the number $7$ is called the multiplier.
The process of the inverse of the multiplication method is called division operation. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. We usually need to memorize the multiplication tables in childhood so it will help to do mathematics.
Complete step-by-step solution:
Since given that we have the information of One-second of the number is eight less than the number.
Let us fix the unknown number that we need to find as $x$
Thus, one-second of the number means $\dfrac{1}{2}x$ also given that the eight is less than the number, which is expressed as mathematically as $x - 8$.
Hence the One-second of the number is eight less than the number expressed as $\dfrac{1}{2}x = x - 8$
Now we will multiple both terms with the number $2$ then we get $2 \times \dfrac{1}{2}x = 2(x - 8)$
By the division we have $2 \times \dfrac{1}{2}x = 2(x - 8) \Rightarrow x = 2x - 16$
Taking the variables on the left side and numbers on the right side we get $x - 2x = - 16$ and by subtraction, we get $ - x = - 16$ and again by division we get $x = 16$
Hence, we found the unknown number as $16$.
Note: The four major operations in mathematics are addition, subtraction, multiplication, and division.
The addition is the summing of two or more than two numbers, or values, or variables, and in addition if we sum the two or more numbers a new frame of the number will be found.
Subtraction is the minus of two or more than two numbers or values example $2 - 3 = - 1$ (larger number signs stays constant)
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$is called the multiplicand and the number $7$ is called the multiplier.
The process of the inverse of the multiplication method is called division operation. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. We usually need to memorize the multiplication tables in childhood so it will help to do mathematics.
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