
One slice of bread contains 100 calories. How many calories do you reduce if you omit a slice of bread per day for 30 days?
Answer
548.7k+ views
Hint: In this question, we are given the calories that one slice of bread contains, if we omit one slice of bread per day for 30 days then we have to find the calories reduced. So, we will have to first find the total number of slices of bread omitted in 30 days, we will find it by adding the number of slices of bread omitted each day. As 1 bread is omitted per day, so we will add 1 to itself 30 times, or we can simply multiply 1 by 30. Now, we will get the total number of slices of bread omitted in 30 days, to find the total number of calories omitted, we will express bread in terms of calories and thus get the correct answer.
Complete step-by-step solution:
We know that 1 slice of bread is omitted per day, so the number of slices of bread omitted in 30 days is \[1 \times 30 = 30\]
Now, calories in one slice of bread $ = 100$
So, calories in 30 slices of bread $30 \times 100 = 3000$
Hence if we omit a slice of bread per day for 30 days then we reduce 3000 calories.
Note: By using algebra in the given question, we can find the number of calories in any number of slices of bread. The alphabets in the algebraic expression represent some unknown quantity that is related to the constants in the algebraic expression. So, letting the number of slices of bread “x”, we get that the calories in “x” slices of bread is $x \times 100 = 100x$ .
Complete step-by-step solution:
We know that 1 slice of bread is omitted per day, so the number of slices of bread omitted in 30 days is \[1 \times 30 = 30\]
Now, calories in one slice of bread $ = 100$
So, calories in 30 slices of bread $30 \times 100 = 3000$
Hence if we omit a slice of bread per day for 30 days then we reduce 3000 calories.
Note: By using algebra in the given question, we can find the number of calories in any number of slices of bread. The alphabets in the algebraic expression represent some unknown quantity that is related to the constants in the algebraic expression. So, letting the number of slices of bread “x”, we get that the calories in “x” slices of bread is $x \times 100 = 100x$ .
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