Question

One litre of \[\text{C}{{\text{O}}_{\text{2}}}\]is passed through red hot coke. The volume becomes 1.4 litres at the same temperature and pressure. The composition product is:

Answer 1

Hint: Try to solve this concept using the basics of mole concept. Also keep in mind that passing carbon dioxide over red hot coke reduces carbon dioxide.

Complete step by step answer:
According to the question, one liter of \[\text{C}{{\text{O}}_{\text{2}}}\] is passed through red to coke. As a result of which the volume becomes 1.4 liters at the same temperature and pressure. We need to calculate the composition of the product.
In this reaction, Carbon dioxide gets reduced to form carbon monoxide.
Let us begin by writing the equation.
Therefore, \[\text{C}{{\text{O}}_{\text{2}}}\text{+C}\to \text{2CO}\]
Let the volumes of \[\text{C}{{\text{O}}_{\text{2}}}\], \[\text{C}\] and \[\text{2CO}\] be 1v, 1v and 2v respectively.
Let us assume that ‘x’ liters of \[\text{C}{{\text{O}}_{\text{2}}}\]gives 2x liters of CO
Therefore, the remaining volume of \[\text{C}{{\text{O}}_{\text{2}}}\]= (1-x)
Given, total volume = 1.4 liters
Therefore,
(1 - x) + 2x = 1.4
1 + x = 1.4
x = 0.4 liter
Since CO = 2x = 2×0.4
Therefore, CO = 0.8 liters
Also, Volume of \[\text{C}{{\text{O}}_{\text{2}}}\] = 1.4 - 0.8 = 0.6 liters.
Therefore, the answer is – The composition of the product is 0.8 liters of CO and 0.6 liters of \[\text{C}{{\text{O}}_{\text{2}}}\].

Note: The ‘coke’ given in the question refers to a grey, hard, and porous fuel with a high carbon content and few impurities, that is made by heating coal or oil in the absence of air—a destructive distillation process.