Answer
Verified
393.9k+ views
Hint: Oxygen exists in the form of a gas in its free state. But before diving into the question, let us first understand some basic concepts. The atomic number of oxygen is 8. Hence, this means that there are 8 protons and 8 electrons in an oxygen. From this and by Aufbau’s Principle, we can say that Oxygen has an electronic configuration as follows: \[1{s^2}2{s^2}2{p^4}\].
Complete step by step answer:
This shows us that there are only 4 electrons present in the valence subshell, i.e. 2p. This means that the valence orbital is only partially filled, which in turn reduces the stability of the atom. To increase its stability, oxygen atom forms pi- pi bonds with itself thus satisfying the outer electronic configuration of the oxygen atom. Because of this reason, oxygen exists as a 2-atom molecule in its free state, thus attaining the molecular formula \[{O_2}\].
Hence, whenever we represent oxygen as an element, we represent its most stable form, i.e. \[{O_2}\].
Hence, one gram molecule of oxygen represents one mole of \[{O_2}\]
Hence, Option B is the correct option.
Note:
Oxygen also exists in a uni-atom molecule or tri-atom molecule structure. But these forms of oxygen are relatively less stable than \[{O_2}\] and also their natural abundance is lower. Hence, these are not considered while writing the properties of oxygen as an element.
Complete step by step answer:
This shows us that there are only 4 electrons present in the valence subshell, i.e. 2p. This means that the valence orbital is only partially filled, which in turn reduces the stability of the atom. To increase its stability, oxygen atom forms pi- pi bonds with itself thus satisfying the outer electronic configuration of the oxygen atom. Because of this reason, oxygen exists as a 2-atom molecule in its free state, thus attaining the molecular formula \[{O_2}\].
Hence, whenever we represent oxygen as an element, we represent its most stable form, i.e. \[{O_2}\].
Hence, one gram molecule of oxygen represents one mole of \[{O_2}\]
Hence, Option B is the correct option.
Note:
Oxygen also exists in a uni-atom molecule or tri-atom molecule structure. But these forms of oxygen are relatively less stable than \[{O_2}\] and also their natural abundance is lower. Hence, these are not considered while writing the properties of oxygen as an element.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Select the word that is correctly spelled a Twelveth class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE