Question

On adding a drop of barium chloride to an aqueous solution of sodium sulphite, white precipitate is obtained. Write a balanced chemical equation.

Answer 1

Hint: You should know what white precipitate we have obtained and what type of reaction is happening to solve these kinds of questions.

Complete step-by-step answer:
According to the question when we add a drop of barium chloride to an aqueous solution of sodium sulphite, a white precipitate is obtained.
Now, we know that when barium chloride reacts to aqueous solution of sodium sulphite then it forms Barium sulphite and sodium chloride.
So we can write a balanced chemical equation for the following equation.
The balanced equation for this reaction can be written as: $BaC{l_2} + N{a_2}S{O_3} \to BaS{O_3} + 2NaCl$
Here, Barium sulphite ($BaSO_3$) is the white precipitate formed.
Moreover, this reaction is also a Double displacement reaction.

NOTE: To balance any reaction identify the atoms in each element, then multiply the number of atoms in each element until both sides are equal, then put the coefficient of how much you multiplied the element by and place it in front of that element.