Question

On a hot summer day, a little mosquito produces a warning sound near your ear at a rate of about \[3000\] wings beat per five second .what is the frequency, in hertz, of this sound ?

Answer 1

Hint: In order to answer the question, to know about the frequency of sound produced by the mosquito, in hertz, we will first write all the given values and then we will implement all the given values in the formula of frequency.

Formula used:
$f = \dfrac{n}{t}$
Where, $n$= Number of oscillation, $t$ = Time taken for the particular number of oscillation and $f$ = Frequency of the sound produced.

Complete step by step answer:
Sound waves are measured in hertz (Hz), which is the number of waves that pass through a particular place in a second.
Number of oscillations produced by the mosquito is, $n$ = \[3000\]
Time taken by the mosquito to produce \[3000\] number of oscillation = $5s$
Frequency of vibrating wing of the mosquito is = $f = \dfrac{n}{t}$
So now, implementing all the values in the formula of frequency we will get the frequency as;
$f = \dfrac{n}{t}$
$\Rightarrow f = \dfrac{{3000}}{5} \\
\therefore f = 600\,Hz \\ $
Therefore, the frequency, in hertz, of this sound is $600\,Hz$.

Note:The frequency of sound waves is unaffected by temperature, but the speed of sound in the air is. That speed increases as the temperature rises, as it is exactly proportional to the average speed of air molecules, which rises as the temperature rises.