Answer
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Hint: Use the property of equation .We know an equation has two sides and if we shift a number from one side of an equation to the other side, the sign of the number also changes.
Let a number be $x$.
Complete step-by-step answer:
If we add $x$ to $\frac{{ - 6}}{5}$ we get $\frac{1}{3}$ .
$ \Rightarrow \frac{{ - 6}}{5} + x = \frac{1}{3}$
Now, if we shift $\frac{{ - 6}}{5}$ to the other side of an equation. So, the sign of a number change.
$ \Rightarrow x = \frac{1}{3} + \frac{6}{5}$
Now, take LCM
$
\Rightarrow x = \frac{{5 + 18}}{{15}} \\
\Rightarrow x = \frac{{23}}{{15}} \\
$
So, if $\frac{{23}}{{15}}$ is added to $\frac{{ - 6}}{5}$ then we get $\frac{1}{3}$ .
Note: Whenever we face such types of problems we use some important points. Like we separate the variable from numbers by shifting numbers to other sides of an equation then after taking LCM we can get the required answer.
Let a number be $x$.
Complete step-by-step answer:
If we add $x$ to $\frac{{ - 6}}{5}$ we get $\frac{1}{3}$ .
$ \Rightarrow \frac{{ - 6}}{5} + x = \frac{1}{3}$
Now, if we shift $\frac{{ - 6}}{5}$ to the other side of an equation. So, the sign of a number change.
$ \Rightarrow x = \frac{1}{3} + \frac{6}{5}$
Now, take LCM
$
\Rightarrow x = \frac{{5 + 18}}{{15}} \\
\Rightarrow x = \frac{{23}}{{15}} \\
$
So, if $\frac{{23}}{{15}}$ is added to $\frac{{ - 6}}{5}$ then we get $\frac{1}{3}$ .
Note: Whenever we face such types of problems we use some important points. Like we separate the variable from numbers by shifting numbers to other sides of an equation then after taking LCM we can get the required answer.
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