
Number of one-one functions from A to B where n(A)= 4 and n(B)= 5.
a). 4
b). 5
c). 120
d). 90
Answer
411.6k+ views
Hint: Type of questions is based on the function topic more precisely on the classification of Function. As there are five types of functions
i). one-one function
ii). many one function
iii). onto function
iv). into function
v). Bijective function
Complete step-by-step solution:
One –one function is also known as injective function. A one-one function is a function in which for one input we get one output. As to find one –one function we had a direct formula through which we can easily find the one-one function of ‘A’ to ‘B’.
The formula is \[^{n}{{P}_{m}}\] only if $n\ge m$
In which ‘n’ and ‘m’ are the number of elements of B and A respectively. and where p is for permutation, which is further solved as $\dfrac{n!}{(n-m)!}$
Moving further with our question where
n(A)= number of elements of A= 4= m
n(B)= number of elements of B= 5= n
So by comparing it with above formula ‘m’ = 4 and ‘n’= 5
On solving we will get
\[\begin{align}
& {{=}^{n}}{{P}_{m}} \\
& {{=}^{5}}{{P}_{4}} \\
& =\dfrac{5!}{(5-4)!} \\
& =\dfrac{5!}{1!} \\
& =\dfrac{5\times 4\times 3\times 2\times 1}{1} \\
& =120 \\
\end{align}\]
Hence, the number of one-one functions are 120. So the answer is 120, i.e. option C.
Note: while solving keep in mind that ‘n’ is the number of elements in ‘B’ and ‘m’ is the number of elements in ‘A’. Moreover this formula is only valid when n is greater than or equal to m $n\ge m$ . If it comes out to be less than m than the answer would be zero (0).
i). one-one function
ii). many one function
iii). onto function
iv). into function
v). Bijective function
Complete step-by-step solution:
One –one function is also known as injective function. A one-one function is a function in which for one input we get one output. As to find one –one function we had a direct formula through which we can easily find the one-one function of ‘A’ to ‘B’.
The formula is \[^{n}{{P}_{m}}\] only if $n\ge m$
In which ‘n’ and ‘m’ are the number of elements of B and A respectively. and where p is for permutation, which is further solved as $\dfrac{n!}{(n-m)!}$
Moving further with our question where
n(A)= number of elements of A= 4= m
n(B)= number of elements of B= 5= n
So by comparing it with above formula ‘m’ = 4 and ‘n’= 5
On solving we will get
\[\begin{align}
& {{=}^{n}}{{P}_{m}} \\
& {{=}^{5}}{{P}_{4}} \\
& =\dfrac{5!}{(5-4)!} \\
& =\dfrac{5!}{1!} \\
& =\dfrac{5\times 4\times 3\times 2\times 1}{1} \\
& =120 \\
\end{align}\]
Hence, the number of one-one functions are 120. So the answer is 120, i.e. option C.
Note: while solving keep in mind that ‘n’ is the number of elements in ‘B’ and ‘m’ is the number of elements in ‘A’. Moreover this formula is only valid when n is greater than or equal to m $n\ge m$ . If it comes out to be less than m than the answer would be zero (0).
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE

The highest possible oxidation states of Uranium and class 11 chemistry CBSE

Find the value of x if the mode of the following data class 11 maths CBSE

Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE

A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE

Trending doubts
10 examples of friction in our daily life

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

Define least count of vernier callipers How do you class 11 physics CBSE

The combining capacity of an element is known as i class 11 chemistry CBSE
