
Why is the nomenclature for Mercury (I) Fluoride \[H{g_2}{F_2}\] and not \[HgF\] ?
Answer
475.2k+ views
Hint: Metals are the chemical elements that can easily undergo loss of electrons. Non-metals are the elements that can attract electrons to attain the nearest inert gas configuration. Mercury is a non-metal that combines with fluorine which is a non-metal forms a compound with molecular formula of \[H{g_2}{F_2}\] , the nomenclature can be written based on the oxidation state of central metal atom.
Complete answer:
Chemical elements are of two types based on nature. These are metals, and nonmetals. Metals can easily undergo loss of electrons, and non-metals can try to attract or gain electrons to attain the nearest inert gas configuration. As the inert gases have stable configuration.
Mercury is a non-metal with the chemical symbol \[Hg\], it is having less electronegativity compared to fluorine, where fluorine is the most electronegative element in the periodic table.
Mercury combines with fluorine to form different compounds like \[H{g_2}{F_2}\] and \[HgF\] . but mostly mercury exists as the \[H{g_2}^{2 + }\] only. In the compound \[H{g_2}{F_2}\] , the cation is \[H{g_2}^{2 + }\] .
The empirical formula of \[H{g_2}{F_2}\] is \[HgF\] .
In \[H{g_2}{F_2}\] mercury is the least electronegative element and occupies the central position and fluorine occupies the terminal positions.
The oxidation state of mercury in \[H{g_2}{F_2}\] will be \[2x + 2\left( { - 1} \right) = 0 \Rightarrow x = + 1\]
Thus, the oxidation state of mercury is represented as (I) which means the representation of oxidation number in roman numerals within brackets.
Thus, the nomenclature with Mercury (I) Fluoride is \[H{g_2}{F_2}\] but not \[HgF\]
Note:
Molecular formula is the representation of all the atoms arranged in the compound. Whereas empirical formula is the shortest representation of the atoms present in the molecular formula. In \[H{g_2}{F_2}\] the atoms are in the ratio \[2:2\] , in \[HgF\] the atoms are in \[1:1\] ratio, which is the shortest mole ratio.
Complete answer:
Chemical elements are of two types based on nature. These are metals, and nonmetals. Metals can easily undergo loss of electrons, and non-metals can try to attract or gain electrons to attain the nearest inert gas configuration. As the inert gases have stable configuration.
Mercury is a non-metal with the chemical symbol \[Hg\], it is having less electronegativity compared to fluorine, where fluorine is the most electronegative element in the periodic table.
Mercury combines with fluorine to form different compounds like \[H{g_2}{F_2}\] and \[HgF\] . but mostly mercury exists as the \[H{g_2}^{2 + }\] only. In the compound \[H{g_2}{F_2}\] , the cation is \[H{g_2}^{2 + }\] .
The empirical formula of \[H{g_2}{F_2}\] is \[HgF\] .
In \[H{g_2}{F_2}\] mercury is the least electronegative element and occupies the central position and fluorine occupies the terminal positions.
The oxidation state of mercury in \[H{g_2}{F_2}\] will be \[2x + 2\left( { - 1} \right) = 0 \Rightarrow x = + 1\]
Thus, the oxidation state of mercury is represented as (I) which means the representation of oxidation number in roman numerals within brackets.
Thus, the nomenclature with Mercury (I) Fluoride is \[H{g_2}{F_2}\] but not \[HgF\]
Note:
Molecular formula is the representation of all the atoms arranged in the compound. Whereas empirical formula is the shortest representation of the atoms present in the molecular formula. In \[H{g_2}{F_2}\] the atoms are in the ratio \[2:2\] , in \[HgF\] the atoms are in \[1:1\] ratio, which is the shortest mole ratio.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

