
What is the next term to this series $2,3,7,16,32$ and $57,...$?
A)$94$ B)$93$ C)$92$ D)$95$
Answer
590.4k+ views
Hint: We have to look at the difference of the numbers to notice the pattern which the series follows. Here, the difference is $1,4,9,16,25$ … which are the squares of the given numbers. So the next difference will be $36$ adding it to the last number given in the series will give you the answer.
Complete step-by-step answer:
The given series is $2,3,7,16,32$ and $57,...$
We have to find the next term in the series. We have to look at the difference of the numbers to notice the pattern which the series follows. On observing the pattern of the series we see that on adding $1,4,9,16,25$ … respectively in the series (which are the squares of the natural numbers) we are getting the next term,
$
\Rightarrow 2 + {\left( 1 \right)^2} = 2 + 1 = 3 \\
3 + {\left( 2 \right)^2} = 3 + 4 = 7 \\
7 + {\left( 3 \right)^2} = 7 + 9 = 16 \\
16 + {\left( 4 \right)^2} = 16 + 16 = 32 \\
32 + {\left( 5 \right)^2} = 32 + 25 = 57 \\
{\text{ }} \\
$
So for the next term we'll add the square of $6$ to the last term given in the series.
$ \Rightarrow 57 + {\left( 6 \right)^2} = 57 + 36 = 93$
So the correct answer is ‘B’.
Note: We can also solve this by formula. Since here the difference is the in pattern of the square of the natural numbers, the formula for the ${{\text{n}}^{{\text{th}}}}$ term is-
$ \Rightarrow $ ${{\text{n}}^{{\text{th}}}}$ Term=$\dfrac{{{\text{2}}{{\text{n}}^3} - 3{{\text{n}}^2} + {\text{n + 12}}}}{6}$
Here we have to find ${7^{{\text{th}}}}$ term so on putting the value in formula we get-
$ \Rightarrow {7^{{\text{th}}}}{\text{term = }}\dfrac{{2{{\left( 7 \right)}^3} - 3{{\left( 7 \right)}^2} + 7 + 12}}{6}$
On simplifying the equation, we get,
$ \Rightarrow {7^{{\text{th}}}}{\text{term = }}\dfrac{{2\left( {343} \right) - 3\left( {49} \right) + 19}}{6} = \dfrac{{686 - 147 + 19}}{6} = \dfrac{{558}}{6}$
On dividing the number, we get
$ \Rightarrow {7^{{\text{th}}}}{\text{term = }}\dfrac{{558}}{6} = 93$
So we will get the same answer.
Complete step-by-step answer:
The given series is $2,3,7,16,32$ and $57,...$
We have to find the next term in the series. We have to look at the difference of the numbers to notice the pattern which the series follows. On observing the pattern of the series we see that on adding $1,4,9,16,25$ … respectively in the series (which are the squares of the natural numbers) we are getting the next term,
$
\Rightarrow 2 + {\left( 1 \right)^2} = 2 + 1 = 3 \\
3 + {\left( 2 \right)^2} = 3 + 4 = 7 \\
7 + {\left( 3 \right)^2} = 7 + 9 = 16 \\
16 + {\left( 4 \right)^2} = 16 + 16 = 32 \\
32 + {\left( 5 \right)^2} = 32 + 25 = 57 \\
{\text{ }} \\
$
So for the next term we'll add the square of $6$ to the last term given in the series.
$ \Rightarrow 57 + {\left( 6 \right)^2} = 57 + 36 = 93$
So the correct answer is ‘B’.
Note: We can also solve this by formula. Since here the difference is the in pattern of the square of the natural numbers, the formula for the ${{\text{n}}^{{\text{th}}}}$ term is-
$ \Rightarrow $ ${{\text{n}}^{{\text{th}}}}$ Term=$\dfrac{{{\text{2}}{{\text{n}}^3} - 3{{\text{n}}^2} + {\text{n + 12}}}}{6}$
Here we have to find ${7^{{\text{th}}}}$ term so on putting the value in formula we get-
$ \Rightarrow {7^{{\text{th}}}}{\text{term = }}\dfrac{{2{{\left( 7 \right)}^3} - 3{{\left( 7 \right)}^2} + 7 + 12}}{6}$
On simplifying the equation, we get,
$ \Rightarrow {7^{{\text{th}}}}{\text{term = }}\dfrac{{2\left( {343} \right) - 3\left( {49} \right) + 19}}{6} = \dfrac{{686 - 147 + 19}}{6} = \dfrac{{558}}{6}$
On dividing the number, we get
$ \Rightarrow {7^{{\text{th}}}}{\text{term = }}\dfrac{{558}}{6} = 93$
So we will get the same answer.
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