
Name the reagents used in the following reactions:
(i) ${\text{C}}{{\text{H}}_3} - {\text{CO}} - {\text{C}}{{\text{H}}_3} \to {\left( {{\text{C}}{{\text{H}}_3}} \right)_2} - {\text{CH}} - {\text{OH}}$
(ii) ${{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{C}}{{\text{H}}_2} - {\text{C}}{{\text{H}}_3} \to {{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{CO}}{{\text{O}}^ - }{{\text{K}}^ + }$
Answer
566.1k+ views
Hint: In the first reaction, ketone is converted to alcohol and thus, it is a reduction reaction. In the second reaction, alkylbenzene is oxidized and thus, it is an oxidation reaction.
Complete step by step answer:
(i) Consider the reaction,
${\text{C}}{{\text{H}}_3} - {\text{CO}} - {\text{C}}{{\text{H}}_3} \to {\left( {{\text{C}}{{\text{H}}_3}} \right)_2} - {\text{CH}} - {\text{OH}}$
In the given reaction, acetone is converted to 2-propanol.
The reaction involves reduction of a ketone to alcohol.
Thus, the reducing agent used to convert acetone to alcohol is sodium borohydride $\left( {{\text{NaB}}{{\text{H}}_{\text{4}}}} \right)$.
Thus, the reagent used in the reaction is ${\text{NaB}}{{\text{H}}_{\text{4}}}$.
Thus,
${\text{C}}{{\text{H}}_3} - {\text{CO}} - {\text{C}}{{\text{H}}_3}\xrightarrow{{{\text{NaB}}{{\text{H}}_{\text{4}}}}}{\left( {{\text{C}}{{\text{H}}_3}} \right)_2} - {\text{CH}} - {\text{OH}}$
(ii) Consider the reaction,
${{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{C}}{{\text{H}}_2} - {\text{C}}{{\text{H}}_3} \to {{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{CO}}{{\text{O}}^ - }{{\text{K}}^ + }$
In the given reaction, alkylbenzene is converted to its acidic salt.
The reaction involves oxidation of an alkylbenzene.
Thus, the reducing agent used for the oxidation of alkylbenzene is alkaline solution of potassium permanganate $\left( {{\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}} \right)$.
Thus, the reagent used in the reaction is ${\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}$.
Thus,
${{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{C}}{{\text{H}}_2} - {\text{C}}{{\text{H}}_3}\xrightarrow{{{\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}}}{{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{CO}}{{\text{O}}^ - }{{\text{K}}^ + }$
Note: Sodium borohydride $\left( {{\text{NaB}}{{\text{H}}_{\text{4}}}} \right)$ is white coloured powder in appearance. It does not have any odour i.e. it is odourless. Sodium borohydride is a good reducing reagent for the reduction of aldehydes and ketones to alcohols. It is also used for bleaching of wood pulp, blowing agent for plastics. But sodium borohydride is a mild reducing agent. Thus, for reducing esters to alcohols which is a slow reaction excess of sodium borohydride is required.
Potassium permanganate $\left( {{\text{KMn}}{{\text{O}}_{\text{4}}}} \right)$ is a strong oxidising agent. Thus, it readily accepts electrons from other substances. Alkaline solution of potassium permanganate $\left( {{\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}} \right)$ is generally used. It is also used as a mild antiseptic and a drying agent on infected areas of the skin. It is an effective disinfectant to sanitize green leafy vegetables and fruits.
Complete step by step answer:
(i) Consider the reaction,
${\text{C}}{{\text{H}}_3} - {\text{CO}} - {\text{C}}{{\text{H}}_3} \to {\left( {{\text{C}}{{\text{H}}_3}} \right)_2} - {\text{CH}} - {\text{OH}}$
In the given reaction, acetone is converted to 2-propanol.
The reaction involves reduction of a ketone to alcohol.
Thus, the reducing agent used to convert acetone to alcohol is sodium borohydride $\left( {{\text{NaB}}{{\text{H}}_{\text{4}}}} \right)$.
Thus, the reagent used in the reaction is ${\text{NaB}}{{\text{H}}_{\text{4}}}$.
Thus,
${\text{C}}{{\text{H}}_3} - {\text{CO}} - {\text{C}}{{\text{H}}_3}\xrightarrow{{{\text{NaB}}{{\text{H}}_{\text{4}}}}}{\left( {{\text{C}}{{\text{H}}_3}} \right)_2} - {\text{CH}} - {\text{OH}}$
(ii) Consider the reaction,
${{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{C}}{{\text{H}}_2} - {\text{C}}{{\text{H}}_3} \to {{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{CO}}{{\text{O}}^ - }{{\text{K}}^ + }$
In the given reaction, alkylbenzene is converted to its acidic salt.
The reaction involves oxidation of an alkylbenzene.
Thus, the reducing agent used for the oxidation of alkylbenzene is alkaline solution of potassium permanganate $\left( {{\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}} \right)$.
Thus, the reagent used in the reaction is ${\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}$.
Thus,
${{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{C}}{{\text{H}}_2} - {\text{C}}{{\text{H}}_3}\xrightarrow{{{\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}}}{{\text{C}}_6}{{\text{H}}_{\text{5}}} - {\text{CO}}{{\text{O}}^ - }{{\text{K}}^ + }$
Note: Sodium borohydride $\left( {{\text{NaB}}{{\text{H}}_{\text{4}}}} \right)$ is white coloured powder in appearance. It does not have any odour i.e. it is odourless. Sodium borohydride is a good reducing reagent for the reduction of aldehydes and ketones to alcohols. It is also used for bleaching of wood pulp, blowing agent for plastics. But sodium borohydride is a mild reducing agent. Thus, for reducing esters to alcohols which is a slow reaction excess of sodium borohydride is required.
Potassium permanganate $\left( {{\text{KMn}}{{\text{O}}_{\text{4}}}} \right)$ is a strong oxidising agent. Thus, it readily accepts electrons from other substances. Alkaline solution of potassium permanganate $\left( {{\text{KMn}}{{\text{O}}_{\text{4}}} - {\text{KOH}}} \right)$ is generally used. It is also used as a mild antiseptic and a drying agent on infected areas of the skin. It is an effective disinfectant to sanitize green leafy vegetables and fruits.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

