
How many N atoms are there in one mole of ${{N}_{2}}$ ?
Answer
559.2k+ views
Hint We know that one molecule of ${{N}_{2}}$ contains 2 atoms of N. To calculate the number of N atoms in one mole of ${{N}_{2}}$, we need to have basic knowledge of mole concept.
Complete step by step solution:
Let us study the mole concept in detail;
One mole- The basic definition of one mole is the presence of Avogadro’s number of particles in it. In short, one mole of a substance contains Avogadro’s number of particles.
Avogadro’s number is equal to $6.022\times {{10}^{23}}$ entities and is represented as ${{N}_{A}}$.
Now, moving towards the given illustration;
We know that by definition, one mole of nitrogen gas will have $6.022\times {{10}^{23}}$molecules. But the molecule of nitrogen contains two atoms of nitrogen thus,
$6.022\times {{10}^{23}}molecules\left( {{N}_{2}} \right)\times \dfrac{2atoms\left( N \right)}{1molecule\left( {{N}_{2}} \right)}=1.2044\times {{10}^{24}}atoms\left( N \right)$.
Note: Do note that in general we can represent the same answer in short form as $2\times {{N}_{A}}$ where, ${{N}_{A}}$ is the Avogadro’s number or constant.
Under the standard conditions, nitrogen is colourless, odourless diatomic gas. Thus, if the formula is not given then we can simply find the number of molecules in one mole of nitrogen by the definition.
Complete step by step solution:
Let us study the mole concept in detail;
One mole- The basic definition of one mole is the presence of Avogadro’s number of particles in it. In short, one mole of a substance contains Avogadro’s number of particles.
Avogadro’s number is equal to $6.022\times {{10}^{23}}$ entities and is represented as ${{N}_{A}}$.
Now, moving towards the given illustration;
We know that by definition, one mole of nitrogen gas will have $6.022\times {{10}^{23}}$molecules. But the molecule of nitrogen contains two atoms of nitrogen thus,
$6.022\times {{10}^{23}}molecules\left( {{N}_{2}} \right)\times \dfrac{2atoms\left( N \right)}{1molecule\left( {{N}_{2}} \right)}=1.2044\times {{10}^{24}}atoms\left( N \right)$.
Note: Do note that in general we can represent the same answer in short form as $2\times {{N}_{A}}$ where, ${{N}_{A}}$ is the Avogadro’s number or constant.
Under the standard conditions, nitrogen is colourless, odourless diatomic gas. Thus, if the formula is not given then we can simply find the number of molecules in one mole of nitrogen by the definition.
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