Question

Multiply 132, 124 by Urdhwtirgbhyaam method of vedic mathematics.
(A) 15348
(B) 17548
(C) 16368
(D) None of these

Answer 1

Hint: In this question two numbers are given and we have to multiply them by using the Urdhwtirgbhyaam method of vedic mathematics. This method is a shortcut method of multiplying two numbers. In this method the multiplication of the numbers starts from the left to right side column wise multiplication

Complete step-by-step answer:
The given numbers for the multiplication are – 132 and 124
Now writing the numbers in column form and solving by using the Urdhwtirgbhyaam method represented by this diagram given below -

The step by step process of solving the multiplication of 3-digit number is given below -
(1) Starting from the left side, multiply the first digits of both the numbers.
So,
 $ \Rightarrow 1 \times 1 = 1 $

(2) Then do the Cross Multiplication and Addition of the first two digits of both the numbers.
So,
 $
\Rightarrow \left( {1 \times 3} \right) + \left( {2 \times 1} \right) = 3 + 2\\
 = 5
 $

(3) Now do a Cross Multiplication and Addition of all the three digits of both the numbers.
So,
 $
\Rightarrow \left( {1 \times 2} \right) + \left( {4 \times 1} \right) + \left( {2 \times 3} \right) = 2 + 4 + 6\\
 = 12
 $
Since it is a two-digit number so we carry forward the initial number of 12 which is 1 to the previous number which is 5. So, now the answer in the second step becomes
 $ \Rightarrow 5 + 1\left( {{\rm{carry}}} \right) = 6 $ .

(4) Now similar to the second step, do the Cross Multiplication and Addition of the last two digits of both the numbers.
So,
 $
\Rightarrow \left( {2 \times 2} \right) + \left( {4 \times 3} \right) = 4 + 12\\
 = 16
 $
(5) Similarly, as the first step, now multiply the last digits of both the numbers.
So,
 $ \Rightarrow 4 \times 2 = 8 $
6) After the multiplication, if there are two-digit numbers in one column then carry forward initial digits to the previous column place.
so, in the step (4) the number we have obtained is a two-digit number which is 16 so we carry forward the initial number of 16 which is 1 to the previous number obtained in the step (3).
So, the answer in the step (4) becomes 6 and the answer in the step (3) becomes $ 12 + 1\left( {{\rm{carry}}} \right) = 13 $
Similarly, in the step (3) the number we have obtained which is 13 is also a two-digit number so we carry forward the initial number of 13 which is 1 to the previous number obtained in the step (2).
So, the answer in the step (3) becomes 3 and the answer in the step (2) becomes $ 5 + 1\left( {{\rm{carry}}} \right) = 6 $
Now combining all numbers obtained in step (1), (2), (3), (4), (5) and (6) we get the answer of the multiplication as –
 $ \Rightarrow 132 \times 124 = 16368 $

So, the correct answer is “Option C”.

Note: It should be noted that this method is only useful if the number of the digits for the multiplication are less such as two, three or four digits. But if the numbers of the digits to multiply is large then the multiplication process becomes more complex. Also, one limitation of Urdhwtirgbhyaam method is that the multiplication is possible only if the two numbers have the same number of digits.