
Mr. Mohan has Rs. 256 in the form of Rs. 1 and Rs. 2 coins. If the number Rs. 2 coins are three more than twice the number of Rs. 1 coins, find the total value of Rs. 2 coins.
(a) Rs. 250
(b) Rs. 205
(c) Rs. 206
(d) Rs. 210
Answer
548.1k+ views
Hint: In this problem, from our given problem we are trying to find the total value of the Rs. 2 coins. To do that, we need to first find out the number of Rs. 2 coins in the lot and then find the value. So, to start with we consider the total number of the Rs. 1 coins be x. And thus we get the total number of the Rs. 2 coins to be 2x + 3. From this analyzing the problem and simplifying we get the value of x and our needed value.
Complete step-by-step solution:
Let, the total number of the Rs. 1 coins be x.
Then the total number of the Rs. 2 coins will be 2x + 3.
And also the total value of the coins is Rs. 256.
So, now the total value of the Rs. 1 coins will be, $Rs.\left( 1\times x \right)=Rs.x$
And again, the total value of the Rs. 2 coins will be, $Rs.\left( 2\times \left( 2x+3 \right) \right)=Rs.\left( 4x+6 \right)$
Hence, the total value of the coins is, $Rs.x+\left( 4x+6 \right)=Rs.\left( 5x+6 \right)$
Now, it is also given that the value of the coins is, Rs. 256.
Equating them, we are getting,
$5x+6=256$
Subtracting 6 from both sides we get,
$\Rightarrow 5x=250$
Dividing both sides with 5 we are getting,
$\Rightarrow x=50$
So, the total number of Rs. 1 coins is 50.
Then, the total number of Rs. 2 coins is, $=\left( 2\times 50 \right)+3$ $=100+3=103$
Now, the total value of Rs. 2 coins is, $=Rs.\left( 2\times 103 \right)=Rs.206$
Hence the solution is, (c) Rs. 206
Note: In this problem, where we are dealing with money related issues, we need to be very careful about the calculations from the problem. You need to know that these types of problems are very easy to solve and silly mistakes may easily take place in them. So, that is why we need to be cautious about them and get the right solution.
Complete step-by-step solution:
Let, the total number of the Rs. 1 coins be x.
Then the total number of the Rs. 2 coins will be 2x + 3.
And also the total value of the coins is Rs. 256.
So, now the total value of the Rs. 1 coins will be, $Rs.\left( 1\times x \right)=Rs.x$
And again, the total value of the Rs. 2 coins will be, $Rs.\left( 2\times \left( 2x+3 \right) \right)=Rs.\left( 4x+6 \right)$
Hence, the total value of the coins is, $Rs.x+\left( 4x+6 \right)=Rs.\left( 5x+6 \right)$
Now, it is also given that the value of the coins is, Rs. 256.
Equating them, we are getting,
$5x+6=256$
Subtracting 6 from both sides we get,
$\Rightarrow 5x=250$
Dividing both sides with 5 we are getting,
$\Rightarrow x=50$
So, the total number of Rs. 1 coins is 50.
Then, the total number of Rs. 2 coins is, $=\left( 2\times 50 \right)+3$ $=100+3=103$
Now, the total value of Rs. 2 coins is, $=Rs.\left( 2\times 103 \right)=Rs.206$
Hence the solution is, (c) Rs. 206
Note: In this problem, where we are dealing with money related issues, we need to be very careful about the calculations from the problem. You need to know that these types of problems are very easy to solve and silly mistakes may easily take place in them. So, that is why we need to be cautious about them and get the right solution.
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