Question

Monthly income of A and B are in the ratio of 4:3and their savings are in the ratio of 3:2. If the expenditure of each will be Rs.600,what will be the monthly income of B?
A. 2400
B. 1170
C. 1500
D. 1800

Answer 1

Hint- Income would be the sum of expenditure and savings, because whatever a person has to do be it save or spend , it has to be through his income

Complete step-by-step answer:
Given that monthly income of A and B are in the ratio 4:3= 4x:3x
Given that expenditure of A and B would be Rs.600 each
Savings of A and B are in the ratio 3:2=3y:2y
We know that Income=Expenditure + Savings
So, we can write income of A :4x=600+3y
                                                     $ \Rightarrow 4x - 3y = 600$------(i)
                               Income of B: 3x=600+2y
                                                      $ \Rightarrow 3x - 2y = 600$ -------(ii)
On subtracting eq(i)-eq(ii), we get
4x-3y-3x+2y=600-600
$ \Rightarrow $ x-y=0
$ \Rightarrow $ x=y
Now let us substitute the values of x=y in eq(i)
So, we get 4x-3x=600
$ \Rightarrow $x=600
We have been asked to find out the monthly income of B
Monthly income of B =3x=$300 \times 600 = 1,800$
So, therefore the income of B=Rs.1,800
So, option D is the correct answer for this question

Note: When solving these types of questions make sure not to find only the value of x, but also find the required value from the value of x.