Question

How many moles of solute particles are in 1L of \[0.50{\text{M}}\] glucose? Type the number?

Answer 1

Hint:We are already provided with the compound glucose and its molarity. We need to use the basic molarity formula. It is a part of physical chemistry.

Formula used: ${\text{molarity = }}\dfrac{{{\text{moles of solute}}}}{{{\text{litres of solution}}}}$

Complete step-by-step answer:We already know that:
Molarity stands for moles of solute over a litre of solution. This formula only gives us the answer. Therefore, by the definition of molarity, there is 0.5 moles of glucose in each litre of solution. It is denoted by M.
Here, we have a 1 L solution of \[0.50{\text{M}}\] glucose,
$1L \times 0.50{\text{ mol/L}} = 0.50$ moles of glucose
So, there exists $0.5$ moles of glucose molecules in the solution.

Additional Note: We should know that in order to calculate the number of moles of any substance present in the sample, we simply divide the given weight of the substance by its molar mass. Whereas The molarity (M) of a solution is the number of moles of solute dissolved in one litre of solution. To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in litres.

Note:We should also know that here we are dealing with molarity.
Other terms such as molarity, molality, and normality are all units of concentration in chemistry. Molarity is defined as the number of moles of solute per litre of solution. Molality is defined as the number of moles of solute per kilogram of solvent. Normality is defined as the number of equivalents per litre of solution.