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How many moles of NaCl will react completely with 18.5L F2 gas at 300.0K and 1.00mol atm ?
(A) 0.75mol NaCl
(B) 1.33mol NaCl
(C) 1.50mol NaCl
(D) 2.66mol NaCl

Answer
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Hint: For this kind of question we will first have to write balanced equation through which we will get a relation between two quantities of molecules , after that by using basic chemistry formula in which we can use known quantities and find out unknown or required quantity and then by putting the value we got in the previous relation we got through reaction we will get the answer.

Complete step by step solution:
To understand the question better, we will first write down the reaction which is taking place;
 2NaCl+F22NaF+Cl2
The above equation is balanced and from that we know 2mol of NaCl corresponds to 1mol of F2
Now, for calculation of moles of NaCl reacting with F2 , we will first calculate the number of moles of F2 gas.
By using basic ideal gas law;
 pV=nRT
Where p= pressure
 V= volume
 n= number of moles
 R= gas constant
 T= temperature
Now we want to know number of moles every thing is already given and we know R=0.08206L
 n=pVRT=1atm×18.5L0.08206L.atm/K.mol×300K=0.751mol
And as we know one mole of F2 gas corresponds to two moles of NaCl
Moles of NaCl
   =2×0.751=1.50moles.
Therefore, 1.50 moles of NaCl will react completely with 18.5L F2 gas at 300.0K and 1.00mol atm. So, Option (C) is correct.

Note:
The gas constant which we have used in the above example is defined as the product of volume and pressure. It is an important physical constant used in many fundamental equations. We can express it in many ways with different unit systems.
Values of RUnits
8.31 J/mol.K
1.98 C/mol.K
8.31 m3.Pa/mol.K
0.0821 L.atm/mol.K
1.98×103 K.Cal/mol.K
62.36 L.torr/mol.K


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