
How many moles of \[{\text{HCl}}\] will be present in 100 mL of a solution of specific gravity \[1.08\], containing \[20\% \] \[{\text{HCl}}\] by mass?
A.\[{\text{0}}{\text{.50}}\]
B.\[{\text{0}}{\text{.60}}\]
C.\[{\text{0}}{\text{.80}}\]
D.\[{\text{0}}{\text{.12}}\]
Answer
515.4k+ views
Hint: From the given density of solution we can calculate the mass of solution and hence with the mass percentage will get the mass of \[{\text{HCl}}\] in the solution. Number of moles can be calculated using the formula.
Formula used:
\[{\text{n}} = \dfrac{{\text{m}}}{{\text{M}}}\]
here n is the number of moles, m is the mass of substance and M is the molar mass.
\[{\text{D}} = \dfrac{{\text{m}}}{{\text{V}}}\]
Here, D is density, m is mass and V is volume.
Complete step by step answer:
\[{\text{HCl}}\] is hydrochloric acid. Specific gravity is the ratio of the density of the substance to the density of the reference material on whose basis the specific gravity or relative density is calculated. We generally use water as a reference so we can consider specific gravity and density are the same
in this question.
We know the density of the solution and the volume of the solution from the question. Using the formula will calculate the mass of the solution as:
\[{\text{mass of solution}} = 1.08{\text{ g}}/{\text{ml}} \times 100{\text{ ml}} = 108{\text{ g}}\]
Now \[{\text{HCl}}\] is contained \[20\% \] by mass in the solution. So calculating \[20\% \] of the mass of the solution will give us the mass of \[{\text{HCl}}\] as: \[\dfrac{{20}}{{100}} \times 108 = 21.6{\text{ g}}\]
Now we have mass of \[{\text{HCl}}\] the molar mass of \[{\text{HCl}}\] is \[1 + 35.5 = 36.5\].
So the number of moles of \[{\text{HCl}}\] will be: \[\dfrac{{21.6}}{{36.5}} = 0.59{\text{ moles}}\]
Hence the numbers of moles are approximately equal to \[{\text{0}}{\text{.60}}\].
So the correct option is B.
Note:
Hydrochloric acid is an inorganic acid also known as mineral acid. It is a corrosive acid. There are enormous uses of hydrochloric acid such as it is used in pickling of Steel and in synthesis of many organic and inorganic compounds.
Formula used:
\[{\text{n}} = \dfrac{{\text{m}}}{{\text{M}}}\]
here n is the number of moles, m is the mass of substance and M is the molar mass.
\[{\text{D}} = \dfrac{{\text{m}}}{{\text{V}}}\]
Here, D is density, m is mass and V is volume.
Complete step by step answer:
\[{\text{HCl}}\] is hydrochloric acid. Specific gravity is the ratio of the density of the substance to the density of the reference material on whose basis the specific gravity or relative density is calculated. We generally use water as a reference so we can consider specific gravity and density are the same
in this question.
We know the density of the solution and the volume of the solution from the question. Using the formula will calculate the mass of the solution as:
\[{\text{mass of solution}} = 1.08{\text{ g}}/{\text{ml}} \times 100{\text{ ml}} = 108{\text{ g}}\]
Now \[{\text{HCl}}\] is contained \[20\% \] by mass in the solution. So calculating \[20\% \] of the mass of the solution will give us the mass of \[{\text{HCl}}\] as: \[\dfrac{{20}}{{100}} \times 108 = 21.6{\text{ g}}\]
Now we have mass of \[{\text{HCl}}\] the molar mass of \[{\text{HCl}}\] is \[1 + 35.5 = 36.5\].
So the number of moles of \[{\text{HCl}}\] will be: \[\dfrac{{21.6}}{{36.5}} = 0.59{\text{ moles}}\]
Hence the numbers of moles are approximately equal to \[{\text{0}}{\text{.60}}\].
So the correct option is B.
Note:
Hydrochloric acid is an inorganic acid also known as mineral acid. It is a corrosive acid. There are enormous uses of hydrochloric acid such as it is used in pickling of Steel and in synthesis of many organic and inorganic compounds.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE
