
How many moles are in 200 grams of fluorine?
Answer
525.9k+ views
Hint: To solve this question, we first need to understand what is a mole. Mole is the SI unit of measurement and is used to determine the amount of a substance. A mole of any substance has exactly $6.022\times {{10}^{23}}$ particles which can be ions, atoms, electrons, or molecules.
Complete step-by-step answer: We know that if one mole of a substance is present, it has exactly the Avogadro number $({{N}_{A}})$ of particles.
${{N}_{A}}=6.022\times {{10}^{23}}$
Now, the mass of a sample can be given by the sum of the mass of all the particles in it.
So, we can say that the mass of one mole of a compound is equivalent to the mass of all the particles contained in one mole of a substance i.e., $6.022\times {{10}^{23}}$ particles.
The mass of one mole of a substance is known as the molar mass of that substance. Its SI base unit is kg/mol but it is usually expressed in g/mol. It is a bulk property of a substance, not a molecular property.
Now, the molar mass of a sample is given by the mass of the sample substance divided by the number of moles of the substance present in the sample.
\[M=\dfrac{m}{n}\]
So, the number of moles in a given sample can be given by
\[n=\dfrac{m}{M}\]
Where n is the number of moles,
m is the mass of the substance given (in grams), and
M is the molar mass of the substance (in g/mol).
We know that the molar mass of Fluorine (F) is 18.998 g/mol.
It is given to us that the mass of the sample substance is 200 grams.
So, the number of moles of the substance in the sample is
\[
n=\dfrac{200g}{18.998g/mol} \\
n\cong 10.527mol \\
\]
Hence there are approximately 10.527 moles in a sample of 200 grams of Fluorine (F).
Note: It must be noted that in 2019, the SI base unit of molar mass was redefined. According to the new definition, the molar mass constant is
\[{{M}_{u}}=0.99999999965\times {{10}^{-3}}kg/mol\]
And not $1\times {{10}^{-3}}kg/mol$.
But since the change is so insignificant, for practical purposes, the molar mass of an element is still considered to be equivalent to the atomic mass of the element.
Complete step-by-step answer: We know that if one mole of a substance is present, it has exactly the Avogadro number $({{N}_{A}})$ of particles.
${{N}_{A}}=6.022\times {{10}^{23}}$
Now, the mass of a sample can be given by the sum of the mass of all the particles in it.
So, we can say that the mass of one mole of a compound is equivalent to the mass of all the particles contained in one mole of a substance i.e., $6.022\times {{10}^{23}}$ particles.
The mass of one mole of a substance is known as the molar mass of that substance. Its SI base unit is kg/mol but it is usually expressed in g/mol. It is a bulk property of a substance, not a molecular property.
Now, the molar mass of a sample is given by the mass of the sample substance divided by the number of moles of the substance present in the sample.
\[M=\dfrac{m}{n}\]
So, the number of moles in a given sample can be given by
\[n=\dfrac{m}{M}\]
Where n is the number of moles,
m is the mass of the substance given (in grams), and
M is the molar mass of the substance (in g/mol).
We know that the molar mass of Fluorine (F) is 18.998 g/mol.
It is given to us that the mass of the sample substance is 200 grams.
So, the number of moles of the substance in the sample is
\[
n=\dfrac{200g}{18.998g/mol} \\
n\cong 10.527mol \\
\]
Hence there are approximately 10.527 moles in a sample of 200 grams of Fluorine (F).
Note: It must be noted that in 2019, the SI base unit of molar mass was redefined. According to the new definition, the molar mass constant is
\[{{M}_{u}}=0.99999999965\times {{10}^{-3}}kg/mol\]
And not $1\times {{10}^{-3}}kg/mol$.
But since the change is so insignificant, for practical purposes, the molar mass of an element is still considered to be equivalent to the atomic mass of the element.
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