Question

How many molecules are there in $220\,grams$ of $C{F_4}$ ?

Answer 1

Hint: We know that there are $6.022\, \times \,{10^{23}}$ amount of particles in one mole of any atom. Here there are given molecules in place of atoms which we generally use for calculation, so a basic requirement for these types of questions is that We must have basic knowledge of relation between moles and particles.

Complete step-by-step answer:
We know that carbon is tetravalent in nature it means it can make four bonds, now the compound given above is carbon tetrafluoride fluorine which is more electronegative than carbon makes polar bonds. We know methane as a simple tetravalent compound of carbon, in place of hydrogens, fluorine are attached.

Now for calculating the number of molecules we have to firstly change the mass into moles by dividing the mass with molar mass of the compound.
$No.\,of\,moles = \,\dfrac{{given\,mass}}{{molar\,mass}}$

Molar mass of $C{F_4}$ is $88.005\,g\,mo{l^{ - 1}}$ putting it in the formula, we get $No.\,of\,moles = \,\dfrac{{220\,g\,}}{{88.005\,g\,mo{l^{ - 1}}}}$ = $2.499\,moles$. So as we have calculated that the number of moles present are $2.499\,moles$ now let’s start calculating the molecules,
$1\,mole = \,6.022\, \times \,{10^{23}}\,atoms$
Number of particles in $2.499\,moles$ = $6.022\, \times \,{10^{23}}\, \times \,2.499\,molecules$
Number of particles in $2.499\,moles$ = $15.054\, \times \,{10^{23}}\,molecules$
Number of particles in $2.499\,moles$ = $1.5054\, \times \,{10^{24}}\,molecules$

Thus we get to know after calculating that $2.499\,moles$ contains $1.5054\, \times \,{10^{24}}\,molecules$. This is the same as we are talking about a simple mathematical calculation for the number of balls. Suppose We have a box, in that box We have three balls now for calculating the number of balls in four same types of boxes, We have to multiply three balls with four boxes to get the total number.

Note: We have to understand this concept on the basis of moles and particles, where particles can be atoms, molecules etc. Above we have taken an example where the total numbers of balls are equal to the multiplication of balls in one box with the number of boxes. We can change the amount by shifting the decimal in left and right hand direction.