Question

What is the molecular geometry of $N{O}_3^{-}$ ion?

Answer 1

Hint: The molecular geometry of an ion or molecule can be predicted using valence shell electron pair repulsion theory i.e., VSEPR theory. It is based on assumptions that the lone pair and bond pairs of an ion will be arranged in such a manner, that the force of repulsion is minimized.

Complete answer:
According to VSEPR theory, in a polyatomic molecule or ion i.e., a molecule which consists of more than three atoms, one of the atoms is termed as the central atom while other atoms or ions are bonded to it.
To decide the geometry of a molecule, following rules must be followed:
The central atom must be the least electronegative atom because it donates its electrons to show an electropositive character.
The summation of the number of lone pairs or atoms bonded to the central atom via a single bond is known as the steric number of the molecule. It is also known as the VSEPR number. The geometry and hybridization should be assigned according to the steric number of a molecule.
Hence, for $N{O}_3^{-}$ ion, nitrogen will be the central atom because it is less electronegative than oxygen.
Steric number $=3$
Hybridization $=s{p}^2$
Hence, the molecular geometry of $N{O}_3^{-}$ is trigonal planar.

Note:
It is important to note that in $N{O}_3^{-}$ ion, the nitrogen atom cannot form two double bonds with the oxygen atom because its maximum covalency is four. Hence, in the structure it is bonded with two oxygen atoms via double and single bond while forming a dative bond with the third oxygen atom.