
What is the molarity of an aqueous solution containing $22.5$ grams of glucose in $25.5ml$ of solution?
Answer
522.3k+ views
Hint: We realize that the molarity is the most by and large used unit of obsession and is demonstrated by M. It is portrayed as the number of moles of solute present in 1 liter of solution. Thus,
Formula used to figure molarity is,
$Molarity = \dfrac{{{\text{Moles of solute}}}}{{{\text{Volume of solution(L)}}}}$
Complete answer:
Using the formula given in the hint part of the solution one can calculate the molarity of the solution
Given:
The mass of glucose is $22.5g$.
The volume of solution is $25.5mL$
Start by ascertaining the quantity of moles of glucose present in $25.5ml$ of solution.
To do that, utilize the molar mass of glucose.
$Moles\left( {glu\cos e} \right) = \dfrac{{22.5g}}{{180.156g/mol}} = 0.1249moles$
The number of moles of glucose in the solution is $0.1249moles$.
Presently, to discover the molarity of the solution, you need to decide the quantity of moles of solute present in
\[1{\text{ }}L = {10^3}mL\].
The way that you're managing solutions, which, as you probably are aware, is a heterogeneous blend, for example it has a similar organization all through, you can utilize the referred to structure as a change factor to track down the quantity of moles of solute present in \[{10^3}\] mL of solution.
The volume of the solution becomes $0.0255L$
The molarity of the solution is calculated as,
$Molarity = \dfrac{{0.1249}}{{0.0255}} = 4.898M$
Note:
We have to remember that the concentrations in molality are utilized in the examination of fume pressing factor and temperature changes-related arrangement properties. Molality is picked in light of the fact that it’s worth, with varieties in temperature, doesn't change. Then again, the volume of a solution is emphatically temperature-dependent. Molarity is perhaps the most well-known units used to evaluate the centralization of a solution addressing the measure of moles of dissolvable per liter of arrangement (moles/liter). Molarity might be utilized to quantify the dissolvable volume or the solute amount.
Formula used to figure molarity is,
$Molarity = \dfrac{{{\text{Moles of solute}}}}{{{\text{Volume of solution(L)}}}}$
Complete answer:
Using the formula given in the hint part of the solution one can calculate the molarity of the solution
Given:
The mass of glucose is $22.5g$.
The volume of solution is $25.5mL$
Start by ascertaining the quantity of moles of glucose present in $25.5ml$ of solution.
To do that, utilize the molar mass of glucose.
$Moles\left( {glu\cos e} \right) = \dfrac{{22.5g}}{{180.156g/mol}} = 0.1249moles$
The number of moles of glucose in the solution is $0.1249moles$.
Presently, to discover the molarity of the solution, you need to decide the quantity of moles of solute present in
\[1{\text{ }}L = {10^3}mL\].
The way that you're managing solutions, which, as you probably are aware, is a heterogeneous blend, for example it has a similar organization all through, you can utilize the referred to structure as a change factor to track down the quantity of moles of solute present in \[{10^3}\] mL of solution.
The volume of the solution becomes $0.0255L$
The molarity of the solution is calculated as,
$Molarity = \dfrac{{0.1249}}{{0.0255}} = 4.898M$
Note:
We have to remember that the concentrations in molality are utilized in the examination of fume pressing factor and temperature changes-related arrangement properties. Molality is picked in light of the fact that it’s worth, with varieties in temperature, doesn't change. Then again, the volume of a solution is emphatically temperature-dependent. Molarity is perhaps the most well-known units used to evaluate the centralization of a solution addressing the measure of moles of dissolvable per liter of arrangement (moles/liter). Molarity might be utilized to quantify the dissolvable volume or the solute amount.
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