# Mohan bought 8 oranges for $Rs 4.80$ . If John has $Rs 7.20$ , how many oranges more than Mohan can he buy.

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Hint: To solve this type of question, we can apply the unitary method. The unitary method is a technique in which we can find the value of multiple units by stepwise, finding the value of a single unit. The value of a single unit is first to find out with the help of the given value of the multiple units. This method can also be used to solve various linear equations.

We are given that,
Money Mohan had = $Rs 4.80$
Number of oranges Mohan brought =8
Money John has = $Rs 7.20$
We need to find the number of oranges John can buy, so we find the required number of oranges stepwise.
Step1: we will first find the number of oranges brought for $1Re$ .
To find the number of oranges for $1Re$ we will use the given information.
Now according to the question Mohan buys 8 oranges for $Rs 4.80$ .
Therefore, the number of oranges brought for
$1Re$ = $\dfrac{8}{{4.80}} = 1.66$
Step2: we will find the number of oranges John can buy.
From the above step we have the number of oranges for $1Re$
Now the number of oranges brought for $1Re$ is 1.66.
John has $Rs 7.20$ number of oranges he can buy
= $7.20 \times 1.66 = 11.95$
But 11.95 numbers of oranges do not make any sense because the number of oranges can only have an integral value. So either the number should be 12 or 11, but to buy 12 oranges John has to pay an extra amount. So he can only buy 11 oranges.
Therefore, John can buy 3 more oranges as compared to Mohan.
So, the correct answer is “3”.

Note: In these types of questions, students may get confused because of the fractional values of the units, which must have integral values, so in that case, they must consider an integral part only rather than considering the whole value. Also, students must be aware of how to apply the unitary method to find the accurate values of the units.