
Miles purchased \[\dfrac{5}{6}\] lbs of bananas, Philip purchased \[\dfrac{8}{9}\] lbs of oranges. How many fruits did they purchase together?
Answer
536.4k+ views
Hint: This question is from the topic of pre-algebra. In this question, we will find out the total weight of fruits. For that, we will first understand how to add fractions. After that, we will add the weight of bananas with the weight of oranges to get the total weight of fruits. After solving the further question, we will get our answer.
Complete step by step answer:
Let us solve this question.
In this question, we have given that Miles purchased \[\dfrac{\text{5}}{6}\]lbs of bananas and Philip purchased \[\dfrac{8}{9}\] lbs of oranges. This question has asked us to find the weight of fruits if they purchase together.
Let us first understand how to add fractions.
So, for adding the fractions, we will first make the denominators equal. We will make each denominator of a fraction equal by multiplying a number with the numerator and denominator in that fraction.
After that, we will add the numerators and keep the denominator the same. After that, we will get the addition of two fractions.
So, the weight of total fruits if Miles and Philip purchase together will be
\[\dfrac{\text{5}}{6}+\dfrac{8}{9}\]
The above can also be written as
\[\Rightarrow \dfrac{\text{5}}{6}\times \dfrac{9}{9}+\dfrac{8}{9}\times \dfrac{6}{6}\]
The above term can also be written as
\[\Rightarrow \dfrac{\text{5}\times 9}{6\times 9}+\dfrac{8\times 6}{9\times 6}\]
The above term can also be written as
\[\Rightarrow \dfrac{45}{54}+\dfrac{48}{54}\]
The above term can also be written as
\[\Rightarrow \dfrac{45+48}{54}\]
The above term can also be written as
\[\Rightarrow \dfrac{93}{54}\]
The above can also be written as
\[\Rightarrow \dfrac{31\times 3}{18\times 3}\]
The above can also be written as
\[\Rightarrow \dfrac{31}{18}\]
We can write the above fraction in mixed number as
\[\Rightarrow 1\dfrac{13}{18}\]
Note: We should have a better knowledge in the topic of pre-algebra to solve this type of question easily. We should know how to add fractions. We should know how to convert any improper fraction to mixed fraction. If a mixed number is in the form of \[a\dfrac{c}{b}\], then its improper fraction form will be like \[\dfrac{a\times b+c}{b}\].
Complete step by step answer:
Let us solve this question.
In this question, we have given that Miles purchased \[\dfrac{\text{5}}{6}\]lbs of bananas and Philip purchased \[\dfrac{8}{9}\] lbs of oranges. This question has asked us to find the weight of fruits if they purchase together.
Let us first understand how to add fractions.
So, for adding the fractions, we will first make the denominators equal. We will make each denominator of a fraction equal by multiplying a number with the numerator and denominator in that fraction.
After that, we will add the numerators and keep the denominator the same. After that, we will get the addition of two fractions.
So, the weight of total fruits if Miles and Philip purchase together will be
\[\dfrac{\text{5}}{6}+\dfrac{8}{9}\]
The above can also be written as
\[\Rightarrow \dfrac{\text{5}}{6}\times \dfrac{9}{9}+\dfrac{8}{9}\times \dfrac{6}{6}\]
The above term can also be written as
\[\Rightarrow \dfrac{\text{5}\times 9}{6\times 9}+\dfrac{8\times 6}{9\times 6}\]
The above term can also be written as
\[\Rightarrow \dfrac{45}{54}+\dfrac{48}{54}\]
The above term can also be written as
\[\Rightarrow \dfrac{45+48}{54}\]
The above term can also be written as
\[\Rightarrow \dfrac{93}{54}\]
The above can also be written as
\[\Rightarrow \dfrac{31\times 3}{18\times 3}\]
The above can also be written as
\[\Rightarrow \dfrac{31}{18}\]
We can write the above fraction in mixed number as
\[\Rightarrow 1\dfrac{13}{18}\]
Note: We should have a better knowledge in the topic of pre-algebra to solve this type of question easily. We should know how to add fractions. We should know how to convert any improper fraction to mixed fraction. If a mixed number is in the form of \[a\dfrac{c}{b}\], then its improper fraction form will be like \[\dfrac{a\times b+c}{b}\].
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