Answer
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Hint: Magnesium carbide reacts with water and produces propyne and magnesium hydroxide. This reaction is also known as hydrolysis of magnesium carbide.We can calculate the number of sigma and pi bonds by drawing the structure of propyne correctly.
\[M{g_2}{C_3}{\rm{ }} + {\rm{ }}4{H_2}O{\rm{ }} \to {\rm{ }}2Mg{\left( {OH} \right)_2}{\rm{ }} + {\rm{ }}{C_3}{H_4}\]
Complete Step by step answer: A covalent bond is formed when the sharing of electrons takes place. The covalent bond is of two types one is sigma bond and other one is pie bond.
Sigma bond-This is a type of covalent bond which is formed by the overlapping of orbitals in an end to end fashion. This type of overlapping is also known as axial overlap. When then it is a s-s overlapping and it is also a sigma bond. Similarly, when two p-orbitals overlap then it is a s-p overlapping and it is also an example of sigma bond.
Pi-bond-This is another type of covalent bond which is formed by the overlapping of orbitals in a way that it is parallel to each other and perpendicular to the internuclear axis. This type of overlapping is also known as lateral overlap. When there is a formation of two p orbital overlap. When then it is a p-p overlapping and it is also a pi-bond.
The structure of propyne is
We can clearly see that carbon-1 forms 3 sigma bonds with hydrogen and one sigma bond with carbon numbers. And carbon-2 forms two sigma and two pi-bond while carbon-3 forms only two sigma and two pi-bonds.
In total there are six sigma and two pi bonds.
Hence option (A) Six sigma and two pi bonds, is the correct option.
Note: The Propyne is an alkyne with three carbon atoms. From the structural formula of propyne it is clear that there is one triple and five single bonds. So the number of sigma and pi bonds can be determined with the help of structure itself. Also, due to the greater extent of overlapping in case of sigma bond the sigma bond is stronger than pi bond as it involves lateral overlapping.
\[M{g_2}{C_3}{\rm{ }} + {\rm{ }}4{H_2}O{\rm{ }} \to {\rm{ }}2Mg{\left( {OH} \right)_2}{\rm{ }} + {\rm{ }}{C_3}{H_4}\]
Complete Step by step answer: A covalent bond is formed when the sharing of electrons takes place. The covalent bond is of two types one is sigma bond and other one is pie bond.
Sigma bond-This is a type of covalent bond which is formed by the overlapping of orbitals in an end to end fashion. This type of overlapping is also known as axial overlap. When then it is a s-s overlapping and it is also a sigma bond. Similarly, when two p-orbitals overlap then it is a s-p overlapping and it is also an example of sigma bond.
Pi-bond-This is another type of covalent bond which is formed by the overlapping of orbitals in a way that it is parallel to each other and perpendicular to the internuclear axis. This type of overlapping is also known as lateral overlap. When there is a formation of two p orbital overlap. When then it is a p-p overlapping and it is also a pi-bond.
The structure of propyne is
![seo images](https://www.vedantu.com/question-sets/ae308ee0-d32c-471a-a496-385f4a5902a81380357107564493816.png)
We can clearly see that carbon-1 forms 3 sigma bonds with hydrogen and one sigma bond with carbon numbers. And carbon-2 forms two sigma and two pi-bond while carbon-3 forms only two sigma and two pi-bonds.
In total there are six sigma and two pi bonds.
Hence option (A) Six sigma and two pi bonds, is the correct option.
Note: The Propyne is an alkyne with three carbon atoms. From the structural formula of propyne it is clear that there is one triple and five single bonds. So the number of sigma and pi bonds can be determined with the help of structure itself. Also, due to the greater extent of overlapping in case of sigma bond the sigma bond is stronger than pi bond as it involves lateral overlapping.
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