Question

Methane burns readily in air. Write the balanced chemical equation for it.
A. $C{H_4} + {20_2} \to C{O_2} + 2{H_2}O$
B. $C{H_4} + {30_2} \to C{O_2} + 2{H_2}O$
C. $C{H_4} + {50_2} \to 3C{O_2} + 2{H_2}O$
D.$C{H_4} + {70_2} \to 2C{O_2} + 2{H_2}O$

Answer 1

Hint: Combustion is a process in which compound burns in sufficient amounts of oxygen. Generally, carbon dioxide gas produced during combustion.

Step by step answer: Alkane is organic compound having general formula $Cn{H_2}n + 2.$
If $n = 1$ then $C{H_{2 \times 1 + 2}} = C{H_4}$ Methane. Methane is the first member of alkane.
Since, organic compounds contain carbon and hydrogen as main elements therefore they produce carbon di-oxide and water on combustion.
Methane also produces $C{O_2}$ and water on heating with oxygen or air $C{H_4}$ completely oxidized by oxygen.
$C{H_4}(g){20_{2(g)}} \to C{O_{_{2(g)}}} + 2{H_2}{O_{(1)}}$
$\Delta H = - 890KJmol{e^{ - 1}}$
Negative sign represents the exothermic reaction in which heat is evolved during reaction.

Therefore, from the above explanation the correct option is (A) $C{H_4} + {20_2} \to C{O_2} + 2{H_2}O$.

Additional Information: Methane is simplest alkane.
It is the main constituent of natural gas.
It is group$14$hydride. Methane abundantly present on earth.
Therefore, it is an economical fuel.
It is a gaseous compound so strong it processes technical challenge.
It has a tetrahedral structure. Four H-atoms are present at vertices of tetrahedron. The C-atom in methane is $s{p^3}$ hybridized.
$4s{p^3}$ hybrid orbitals of C-atoms form covalent bond with an orbital of $4$ H-atoms.

Note: Methane requires sufficient air. During incomplete combustion of alkane with insufficient amount of air carbon black is formed.
This is used in manufacture of ink, printer ink black pigments etc