
Metallic tin in the presence of HCl is oxidized by ${K_2}C{r_2}{O_7}$ to stannic chloride $SnC{l_4}$. What volume of decinormal dichromate solution would be reduced by 1g of Sn?
Answer
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Hint- In this question ${K_2}C{r_2}{O_7}$ represents a Potassium Dichromate. And it is a common inorganic chemical reagent in various laboratory and industrial applications Potassium Dichromate are used as an oxidizing agent Potassium Dichromate are harmful for our health Potassium Dichromate is a crystalline ionic solid with a extremely bright, red-orange color. Potassium Dichromate is a strong oxidizing agent and is soluble in water. Potassium Dichromate is used to oxidize alcohols.
Complete step-by-step answer:
As we know between the reaction of potassium chloride on sodium dichromate as a resultant Potassium Dichromate is produced. Potassium Dichromate converts primary alcohols into aldehyde. Potassium Dichromate is used as an ingredient in cement.
$SnCl_4$ means stannic chloride it is a colorless fuming liquid stannic chloride decomposed by hot water to form hydrochloric acid chemical with the evolution of heat. Stannic chloride Is very corrosive to metals and tissue.
Hcl means hydrochloric acid; it is a colorless inorganic chemical system. hydrochloric is classified as a strong acid. It is a very dangerous acid and should be used in a proper way. The alchemist Jabir ibn Hayyan is a person who discovered hydrochloric acid. Hydrochloric acid was historically called acidic sails and spirits of salt because this acid is produced from rock salt hydrochloric acid is a solution of hydrogen chloride and water and many other chemical spices. Hydrochloric, hydronium chloride, is other name of hydrochloric acid.
We have, the redox changes
as,
$Sn \to S{n^{4 + }} + 4{e^ - }$
$6{e^ - } + Cr_2^{6 + } \to 2C{r^{3 + }}$
∴ Meq. of Sn = Meq. of ${K_2}C{r_2}{O_7}$
Or $\dfrac{1}{{{E_{sn}}}} \times 1000 = \dfrac{1}{{10}} \times v$
As Equivalent means of ${S_n}$
= $\dfrac{{st.{\text{ }}wt.}}{4}$
Or v = 336.98 ml
Therefore, volume of decinormal dichromate solution would be reduced by 1g of Sn is 336.98ml.
Note: Always remember that Reaction of Sn with water is more reactive than germanium, which is immediately above Sn in the periodic table. It is stable to ${H_2}O$ under ambient conditions but on heating with steam, tin reacts with water to form tin dioxide, $Sn{O_2}$ and hydrogen.
Complete step-by-step answer:
As we know between the reaction of potassium chloride on sodium dichromate as a resultant Potassium Dichromate is produced. Potassium Dichromate converts primary alcohols into aldehyde. Potassium Dichromate is used as an ingredient in cement.
$SnCl_4$ means stannic chloride it is a colorless fuming liquid stannic chloride decomposed by hot water to form hydrochloric acid chemical with the evolution of heat. Stannic chloride Is very corrosive to metals and tissue.
Hcl means hydrochloric acid; it is a colorless inorganic chemical system. hydrochloric is classified as a strong acid. It is a very dangerous acid and should be used in a proper way. The alchemist Jabir ibn Hayyan is a person who discovered hydrochloric acid. Hydrochloric acid was historically called acidic sails and spirits of salt because this acid is produced from rock salt hydrochloric acid is a solution of hydrogen chloride and water and many other chemical spices. Hydrochloric, hydronium chloride, is other name of hydrochloric acid.
We have, the redox changes
as,
$Sn \to S{n^{4 + }} + 4{e^ - }$
$6{e^ - } + Cr_2^{6 + } \to 2C{r^{3 + }}$
∴ Meq. of Sn = Meq. of ${K_2}C{r_2}{O_7}$
Or $\dfrac{1}{{{E_{sn}}}} \times 1000 = \dfrac{1}{{10}} \times v$
As Equivalent means of ${S_n}$
= $\dfrac{{st.{\text{ }}wt.}}{4}$
Or v = 336.98 ml
Therefore, volume of decinormal dichromate solution would be reduced by 1g of Sn is 336.98ml.
Note: Always remember that Reaction of Sn with water is more reactive than germanium, which is immediately above Sn in the periodic table. It is stable to ${H_2}O$ under ambient conditions but on heating with steam, tin reacts with water to form tin dioxide, $Sn{O_2}$ and hydrogen.
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