Mayer’s formula ${C_p} - {C_v} = \dfrac{R}{J}$ is for $1$ gm mole of a gas. If we consider n gm mol. of the gas the formula is (in heat units):
A. ${C_p} - {C_v} = \dfrac{{nR}}{J}$
B. ${C_p} - {C_v} = \dfrac{R}{J}$
C. $n\left( {{C_p} - {C_v}} \right) = \dfrac{R}{J}$
D. ${C_p} - {C_v} = \dfrac{R}{{nJ}}$
Answer
595.2k+ views
Hint: Here we are given the Mayer’s formula for one gm mole of a gas and are asked to find n gm mol of the gas formula. Here we will place the values for “n” gm mole of a gas and simplify for the resultant answer in the standard formula.
Complete step by step answer:
Mayer’s formula is derived by using the difference between the specific heat of a gas at the constant pressure $({C_p})$ and its specific heat at constant volume $({C_v})$ which is equal to the universal gas constant (R) divided with the molecular weight (M) of the gas expressed in “J”.
Mayer’s formula is expressed by –
${C_p} - {C_v} = \dfrac{R}{J}$ (For one gm mole of a gas)
Similarly for “n” gm mole of the gas gives –
${C_p} - {C_v} = \dfrac{{nR}}{J}$
So, the correct answer is “Option A”.
Note:
Always remember the basic standard formulas stating the correlation between the constant pressure, volume and temperature. Generally they are known as the PVT equations. To solve these types of word problems always remember the basic five types of gas laws which deal with how gases behave with respect to the pressure, volume and temperature.
- Boyle’s law
- Charles’ law
- Gay-Lussac’s law
- Combined law
- Ideal Gas law
Always remember all the terminologies and the major and minor differences among each of the laws along with the conditions and the standard formula under each type of laws.
Complete step by step answer:
Mayer’s formula is derived by using the difference between the specific heat of a gas at the constant pressure $({C_p})$ and its specific heat at constant volume $({C_v})$ which is equal to the universal gas constant (R) divided with the molecular weight (M) of the gas expressed in “J”.
Mayer’s formula is expressed by –
${C_p} - {C_v} = \dfrac{R}{J}$ (For one gm mole of a gas)
Similarly for “n” gm mole of the gas gives –
${C_p} - {C_v} = \dfrac{{nR}}{J}$
So, the correct answer is “Option A”.
Note:
Always remember the basic standard formulas stating the correlation between the constant pressure, volume and temperature. Generally they are known as the PVT equations. To solve these types of word problems always remember the basic five types of gas laws which deal with how gases behave with respect to the pressure, volume and temperature.
- Boyle’s law
- Charles’ law
- Gay-Lussac’s law
- Combined law
- Ideal Gas law
Always remember all the terminologies and the major and minor differences among each of the laws along with the conditions and the standard formula under each type of laws.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Which gas is abundant in air class 11 chemistry CBSE

