
Maximum number of atoms are present in which of the following?
(1) 2g atom Fe
(2) 2g molecule ${H_2}O$
(3) 16g $C{H_4}$
(4) 10L ${H_2}O$ (l)
Answer
569.1k+ views
Hint:Calculate the number of moles present in each of the given compounds using their molecular weights and given weights. One mole of a substance consists of Avogadro number of molecules and hence the number of atoms can be calculated accordingly.
Complete answer:
(1) Given 2 grams of Iron atoms. The atomic weight of Iron is $56$ grams. So, $56$ grams of Iron contains Avogadro number i.e, $6.022 \times {10^{23}}$ atoms.
Hence 2 grams of Iron contains $\dfrac{{6.022 \times {{10}^{23}}}}{{56}} \times 2$
This gives $0.215 \times {10^{23}}$ atoms.
(2) Molecular weight of ${H_2}O$ is $18$ grams. Two grams of ${H_2}O$ is given to us.
We can calculate the number of moles as $\dfrac{2}{{18}} = \dfrac{1}{9}$ . One mole consists of $6.022 \times {10^{23}}$ number of molecules and each molecule contains three atoms.
Therefore, the total number of atoms would be $6.022 \times {10^{23}} \times \dfrac{1}{9} \times 3 = 2.006 \times {10^{23}}$
(3) Molecular weight of $C{H_4}$ is $16$ grams. Given to us are $16$ grams. Hence there is one mole of $C{H_4}$ and one mole contains $6.022 \times {10^{23}}$ molecules.
We can calculate the total number of atoms to be $5 \times 6.022 \times {10^{23}} = 30.11 \times {10^{23}}$
(4) We know that $22.4$ liters is one mole. We can calculate the number of moles for $10$ liters to be $\dfrac{{10 \times 1mole}}{{22.4}} = 0.446$ moles.
Number of molecules would be $0.446 \times 6.022 \times {10^{23}}$ which is approximately $2.68 \times {10^{23}}$ molecules.
One molecule consists of three atoms so the number of atoms will be $3 \times 2.68 \times {10^{23}} = 8.04 \times {10^{23}}$
Clearly, we can say that $16g$ of $C{H_4}$ contains the maximum number of atoms.
So the correct answer is Option 3.
Note:
One mole of an atom or a molecule contains Avogadro number of atoms or molecules. If it is a molecule, then one should not forget to change it to atoms by multiplying it by the number of atoms present in one individual molecule.
Complete answer:
(1) Given 2 grams of Iron atoms. The atomic weight of Iron is $56$ grams. So, $56$ grams of Iron contains Avogadro number i.e, $6.022 \times {10^{23}}$ atoms.
Hence 2 grams of Iron contains $\dfrac{{6.022 \times {{10}^{23}}}}{{56}} \times 2$
This gives $0.215 \times {10^{23}}$ atoms.
(2) Molecular weight of ${H_2}O$ is $18$ grams. Two grams of ${H_2}O$ is given to us.
We can calculate the number of moles as $\dfrac{2}{{18}} = \dfrac{1}{9}$ . One mole consists of $6.022 \times {10^{23}}$ number of molecules and each molecule contains three atoms.
Therefore, the total number of atoms would be $6.022 \times {10^{23}} \times \dfrac{1}{9} \times 3 = 2.006 \times {10^{23}}$
(3) Molecular weight of $C{H_4}$ is $16$ grams. Given to us are $16$ grams. Hence there is one mole of $C{H_4}$ and one mole contains $6.022 \times {10^{23}}$ molecules.
We can calculate the total number of atoms to be $5 \times 6.022 \times {10^{23}} = 30.11 \times {10^{23}}$
(4) We know that $22.4$ liters is one mole. We can calculate the number of moles for $10$ liters to be $\dfrac{{10 \times 1mole}}{{22.4}} = 0.446$ moles.
Number of molecules would be $0.446 \times 6.022 \times {10^{23}}$ which is approximately $2.68 \times {10^{23}}$ molecules.
One molecule consists of three atoms so the number of atoms will be $3 \times 2.68 \times {10^{23}} = 8.04 \times {10^{23}}$
Clearly, we can say that $16g$ of $C{H_4}$ contains the maximum number of atoms.
So the correct answer is Option 3.
Note:
One mole of an atom or a molecule contains Avogadro number of atoms or molecules. If it is a molecule, then one should not forget to change it to atoms by multiplying it by the number of atoms present in one individual molecule.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

