Question

Match the following: -

List I	List II
A. Perhydrol	1. Rocket fuel
B. Hyperol	2. $100V$ of ${H_2}{O_2}$
C. $3\% \dfrac{w}{v}$ of ${H_2}{O_2}$	3. ${\left( {N{H_2}} \right)_2}Co \cdot {H_2}{O_2}$
D. ${H_2}{O_2}$	4. $1.786\,N\;{H_2}{O_2}$
	5. $N{a_2}HP{O_4} \cdot {H_2}{O_2}$

a. $A - 5,\;B - 3,\;C - 1,\;D - 2$
b. $A - 5,\;B - 3,\;C - 4,\;D - 1$
c. $A - 2,\;B - 3,\;C - 4,\;D - 1$
d. $A - 2,\;B - 4,\;C - 5,\;D - 1$

Answer 1

Hint: A chemical compound with formula ${H_2}{O_2}$ is known as hydrogen peroxide. The oxygen atom in peroxides exists in a $ - 1$ oxidation state and its chemistry is majorly dominated by $O - O$ bond. In its pure form, it exists as a pale blue liquid which has more viscosity as compared to water and widely used as an antiseptic, bleaching and oxidizing agent.

Complete answer:
In the given question, each point is the type of hydrogen peroxide in which it may exist under specific conditions. Let us discuss each point and its match separately as follows:
Perhydrol: A solution which is $30\% $ of weight by volume i.e., $30\% \dfrac{w}{v}$ hydrogen peroxide or $100$ volume of hydrogen peroxide solution is known as Perhydrol. Hence, point A of list I matches with point 2 of list II.
Hyperol: A solution which is a mixture of urea i.e., $N{H_2}CON{H_2}$ and hydrogen peroxide i.e., ${H_2}{O_2}$ and is represented as ${\left( {N{H_2}} \right)_2}Co \cdot {H_2}{O_2}$. Hence, point B of list I matches with point 3 of list II.
$3\% \dfrac{w}{v}$ of ${H_2}{O_2}$: It means that $3g$ of ${H_2}{O_2}$ is present in $100mL$ of solution and equivalent mass of ${H_2}{O_2}$ is as follows:
Equivalent mass of ${H_2}{O_2} = \dfrac{{34}}{2} \Rightarrow 17\;ge{q^{ - 1}}$
So, the normality of the ${H_2}{O_2}$ solution can be determined with the help of given expression:
Normality $ = \dfrac{{{\text{given mass of solute(in grams)}}}}{{{\text{equivalent mass}} \times {\text{Volume(L)}}}}$
Substituting values:
$ \Rightarrow N = \dfrac{{\text{3}}}{{{\text{17}} \times {\text{0}}{\text{.1}}}}$
$ \Rightarrow N = 1.78\;{\text{N}}$
Hence, $3\% \dfrac{w}{v}$ of ${H_2}{O_2}$ represents $1.786\,N\;{H_2}{O_2}$ solution. So, point C of list I matches with point 4 of list II.
High concentration ${H_2}{O_2}$ which is also referred to as high-test peroxide (HTP) can be either used as monopropellant or as an oxidizer component of bipropellant rockets. As a monopropellant, it decomposes to $70 - 98\% $ concentration into oxygen and steam and produces a maximum specific impulse in volume. As a bipropellant, it is decomposed to burn a fuel as an oxidizing agent. Hence, ${H_2}{O_2}$ is used in rocket fuels. So, point D of list I matches with point 1 of list II.
Therefore, the correct matching order is $A - 2,\;B - 3,\;C - 4,\;D - 1$.
Hence C is the correct option.

Note:
Remember that the equivalent mass of a molecule is the exact mass with which it combines or displaces a fixed quantity of another molecule. It can be expressed as $\dfrac{M}{n}$, where M is the molecular mass of the molecule and n is the n-factor or the valency of ions formed on dissociation of the molecule.