Question

What is the mass of one molecule of oxygen?
A. $5.31 \times {10^{ - 23}}g$
B. $5.33 \times {10^{23}}g$
C. $5.25 \times {10^{23}}g$
D. $5.02 \times {10^{ - 23}}g$

Answer 1

Hint: We can arrange the components by expanding mass by determining the measure of the elements in grams. We can decide the amounts of components in grams by changing over the particles which incorporate atoms, molecules into grams. We need to change over the molecules, atoms into grams with the assistance of Avogadro number and atomic mass. The estimation of Avogadro number is $6.022 \times {10^{23}}$.

Complete step by step answer:
We can define molecular mass as the total of the weights of the elements found in the molecule. This could be easily derived by multiplying the known atomic weight of an element by the number of atoms found in the molecule and then by substituting the weights of all elements present in the molecule.
We have to know that One molecule of oxygen has two atoms of oxygen. The value of atomic mass of oxygen is $16g$ . So, the molecular mass of oxygen $\left( {{O_2}} \right)$ becomes $32g$ . We can now obtain the mass of oxygen in grams using the Avogadro number.
We can calculate the mass of oxygen in grams as,
Mass of oxygen=$\dfrac{{32}}{{6.022 \times {{10}^{23}}}}$
Mass of oxygen=$5.31 \times {10^{ - 23}}g$
The mass of 1 molecule of oxygen in grams is $5.31 \times {10^{ - 23}}g$.

So, the correct answer is Option A.

Note: We need to recall that atomic mass in units is changed over to grams by multiplying the Avogadro number. We need to realize that various atoms contain distinctive weight. Along these lines, one mole of molecule (or) atom is diverse in gram too. On the off chance that we don't change the units over to required units there would be mistakes in the conclusive answer.