Question

What is the mass of one mole of magnesium nitrate $Mg{(N{O_3})_2}$?

Answer 1

Hint : The chemical number is another name for mole. An object is anything with mass that takes up space. The estimate of the total mass in grams of the atoms contained in a molecule per mole is the molar mass/molecular weight. The molar mass unit is grams/mole.

Complete Step By Step Answer:
Mole is calculated using this formula:
$n = \dfrac{m}{{{M_r}}}$
Where
$m$is the mass in grams.
${M_r}$is the molecular weight of the substance.
A substance's molecular weight is equal to the numbers of the molecular weights of the individual atoms that make it up.
$
  Mg = 24.3gm \\
  N = 14gm \\
  O = 16gm \\
 $
Now, we know that there is $1 - Mg,2 - N,6 - O$in the compound.
Hence, the molecular weight is
$
  {M_r} = 23 + 2 \times 14 + 6 \times 16 \\
  {M_r} = 147 \\
 $
Substituting these values we get,
$
  n = \dfrac{m}{{{M_r}}} \\
  m = n.{M_r} \\
  m = 1 \times 147 \\
  m = 147gm \\
 $
Hence, The mass of one mole of magnesium nitrate$Mg{(N{O_3})_2}$ is 147grams.

Note :
The mass of a molecule of a substance is measured in molecular weight, which is dependent on 12 as the atomic weight of carbon-12. In fact, it is determined by adding the atomic weights of the atoms that make up the chemical formula of the material.