Question

What is the mass of 5.99 mole of carbon monoxide?

Answer 1

Hint: Number of moles is the measure of the particles in any substance. 1 mole of any compound contains an Avogadro number of atoms or particles that is $6.022\times {{10}^{23}}$ atoms. The mass of these Avogadro number of atoms is equal to the molar mass or atomic mass of any molecule or atom, means in the molar mass of any atom, there will be $6.022\times {{10}^{23}}$ particles.
Formula used:
Number of moles = $\dfrac{given\,mass}{molar\,mass}$

Complete answer:
A mole is the measuring unit given to $6.022\times {{10}^{23}}$particles, atoms or molecules of any substance. This is also known as Avogadro number. The number of moles can be calculated by dividing the mass of the substance upon the molar mass of that substance.
We have been given a carbon monoxide molecule whose chemical formula is CO; we have to find the mass of CO in 5.99 moles of CO. For this we will multiply the molar mass of CO by the given number of moles.
As we know the molar mass of any molecule is the sum of the atomic masses of the atoms in that molecule. We have carbon and oxygen in carbon monoxide whose molar mass is:
Atomic mass of (C + O) = 12 + 16 g/mol
Molar mass of CO = 28 g/mol
Now, we have number of moles = $\dfrac{given\,mass}{molar\,mass}$, rearranging this for finding mass
Mass of CO = number of moles$\times $ molar mass of CO
Mass of CO = 5.99 mol$\times $28 g/mol
Mass of CO = 167.72 g
Hence, the mass of 5.99 moles of carbon monoxide is 167.72 g.

Note:
Apart from using the formula of number of moles we can use conversion factors like,$\dfrac{g}{mol}$ to convert moles into mass, and also$\dfrac{mol}{g}$to convert mass into moles. So this problem can be solved as, $\dfrac{28\,g\,CO}{1\,mol}\times 5.99\,mol$ = 167.72 g. As 28 g of CO comprises 1 mole, so 5.99 mol will have 167.72 g.