
Mark the correct alternative of the following.
The symmetric difference of $ A $ and $ B $ is not equal to ?
(A) $ \left( {A - B} \right) \cap \left( {B - A} \right) $
(B) $ \left( {A - B} \right) \cup \left( {B - A} \right) $
(C) $ \left( {A \cup B} \right) - \left( {A \cap B} \right) $
(D) $ \{ (A \cup B) - A\} \cup \{ (A \cup B) - B\} $
Answer
593.1k+ views
Hint: Symmetric difference of two sets A and B is the union of difference of sets A and B. That is $ A - B $ or $ B - A $. We will see all possible cases and then finally arrive at the conclusion on the basis of definition.
Complete step-by-step answer:
Symmetric difference, $ A\Delta B $ of two sets, A and B is given by
$ A\Delta B = \left( {A - B} \right) \cup \left( {B - A} \right) $
By Venn Diagram, it can be represented as
Clearly, by definition, option (B) satisfies the condition of symmetric difference.
$ A - B $ is the collection of elements that are in A but not in B.
$ \Rightarrow A - B = \{ x:x \in A $ but $ x \notin B\} $
By Venn diagram we can represent it as
$ B - A $ is the collection of elements that are in B but not in A.
$ \Rightarrow B - A = \{ x:x \in B $ but $ x \notin A\} $
By Venn diagram we can represent it as
In the two diagrams, we can clearly observe that there is no element common in $ A - B $ and $ B - A $
$ \Rightarrow \left( {A - B} \right) \cap \left( {B - A} \right) = \phi $
Therefore, $ \left( {A - B} \right) \cap \left( {B - A} \right) $ is not a symmetric difference.
$ \left( {A \cup B} \right) $ is the collection of elements that are either in A or in B or in both.
$ \Rightarrow A \cup B = \{ x:x \in A $ or $ x \in B\} $
By Venn diagram we can represent it as
$ A \cap B $ is the collection of elements that are in both A and B.
$ \Rightarrow A \cap B = \{ x:x \in A $ and $ x \in B\} $
By Venn diagram we can represent it as
Therefore, by observing above two diagrams we can conclude that
By Venn diagram, $ \left( {A \cup B} \right) - \left( {A \cap B} \right) $ can be represented as
Which is exactly like the Venn diagram that represents symmetric difference.
$ (A \cup B) - A $ is the collection of elements that are in $ A \cup B $ but not in A.
$ \Rightarrow (A \cup B) - A = \{ x:A \cup B $ but $ x \notin A\} $
By Venn diagram it can be represented as
$ (A \cup B) - B $ is the collection of elements that are in $ A \cup B $ but not in B.
By Venn diagram it can be represented as
By observing above two diagrams we can conclude that
$ \{ (A \cup B) - A\} \cup \{ (A \cup B) - B\} $ can be represented by Venn diagram as
Which is the same representation as symmetric difference.
Therefore, by above explanation, the correct answer is, option (A) $ \left( {A - B} \right) \cap \left( {B - A} \right) $
So, the correct answer is “Option A”.
Note: From the above question, you can understand the importance of Venn diagram. This question would have been difficult to explain in theory. Diagrammatic representation helped to solve it easily.
Complete step-by-step answer:
Symmetric difference, $ A\Delta B $ of two sets, A and B is given by
$ A\Delta B = \left( {A - B} \right) \cup \left( {B - A} \right) $
By Venn Diagram, it can be represented as
Clearly, by definition, option (B) satisfies the condition of symmetric difference.
$ A - B $ is the collection of elements that are in A but not in B.
$ \Rightarrow A - B = \{ x:x \in A $ but $ x \notin B\} $
By Venn diagram we can represent it as
$ B - A $ is the collection of elements that are in B but not in A.
$ \Rightarrow B - A = \{ x:x \in B $ but $ x \notin A\} $
By Venn diagram we can represent it as
In the two diagrams, we can clearly observe that there is no element common in $ A - B $ and $ B - A $
$ \Rightarrow \left( {A - B} \right) \cap \left( {B - A} \right) = \phi $
Therefore, $ \left( {A - B} \right) \cap \left( {B - A} \right) $ is not a symmetric difference.
$ \left( {A \cup B} \right) $ is the collection of elements that are either in A or in B or in both.
$ \Rightarrow A \cup B = \{ x:x \in A $ or $ x \in B\} $
By Venn diagram we can represent it as
$ A \cap B $ is the collection of elements that are in both A and B.
$ \Rightarrow A \cap B = \{ x:x \in A $ and $ x \in B\} $
By Venn diagram we can represent it as
Therefore, by observing above two diagrams we can conclude that
By Venn diagram, $ \left( {A \cup B} \right) - \left( {A \cap B} \right) $ can be represented as
Which is exactly like the Venn diagram that represents symmetric difference.
$ (A \cup B) - A $ is the collection of elements that are in $ A \cup B $ but not in A.
$ \Rightarrow (A \cup B) - A = \{ x:A \cup B $ but $ x \notin A\} $
By Venn diagram it can be represented as
$ (A \cup B) - B $ is the collection of elements that are in $ A \cup B $ but not in B.
By Venn diagram it can be represented as
By observing above two diagrams we can conclude that
$ \{ (A \cup B) - A\} \cup \{ (A \cup B) - B\} $ can be represented by Venn diagram as
Which is the same representation as symmetric difference.
Therefore, by above explanation, the correct answer is, option (A) $ \left( {A - B} \right) \cap \left( {B - A} \right) $
So, the correct answer is “Option A”.
Note: From the above question, you can understand the importance of Venn diagram. This question would have been difficult to explain in theory. Diagrammatic representation helped to solve it easily.
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