
Maria invested Rs 80,000 in a business. She would be paid interest at 5% per annum compounded annually. Find (i) the amount standing to her credit at the end of the second year. (ii) The interest for the third year.
Answer
513k+ views
Hint: Here we go through by applying the formula of amount after t year at the rate of r% compound i.e. $A = P{\left[ {1 + \dfrac{r}{{100}}} \right]^t}$ here A=amount, P=principal amount, r=rate and t=time.
Here in this question it is given that
Principal, P= Rs. 80,000
Rate of interest, r=5%
And we have to find the amount at the end of two year so t=2.
(i) The amount credited at the end of the second year, $A = P{\left[ {1 + \dfrac{r}{{100}}} \right]^t}$
Now put the values in the formula to find the amount.
$A = 80000{\left( {1 + \dfrac{5}{{100}}} \right)^2} = 80000 \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} = 88200$
Hence, the amount standing to her credit at the end of the second year is Rs. 88200.
Now for solving the (ii) part,
(ii) We have to first calculate the total amount in third year and then for finding the interest for third year we will subtract the amount of two years.
Here Principal, P= Rs. 80,000
Rate of interest, r=5%
And we have to find the amount at the end of three year so t=3.
The amount credited at the end of the third year, $A = P{\left[ {1 + \dfrac{r}{{100}}} \right]^t}$
$A = 80000{\left( {1 + \dfrac{5}{{100}}} \right)^3} = 80000 \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} = 92610$.
Interest of third year=Amount of three years-Amount of two years.
Interest=92610-88200 (as we find the amount for two years above).
=4410
$\therefore $ The interest for the third year is 44410. Answer
Note: Whenever we face such a type of question the key concept for solving the question is you must always remember the formula related to compound interest for solving such a type of question. By putting the given terms in formula you can easily get the answer. And for finding the interest for a specific year just subtract the amount of its previous year from the amount of that year.
Here in this question it is given that
Principal, P= Rs. 80,000
Rate of interest, r=5%
And we have to find the amount at the end of two year so t=2.
(i) The amount credited at the end of the second year, $A = P{\left[ {1 + \dfrac{r}{{100}}} \right]^t}$
Now put the values in the formula to find the amount.
$A = 80000{\left( {1 + \dfrac{5}{{100}}} \right)^2} = 80000 \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} = 88200$
Hence, the amount standing to her credit at the end of the second year is Rs. 88200.
Now for solving the (ii) part,
(ii) We have to first calculate the total amount in third year and then for finding the interest for third year we will subtract the amount of two years.
Here Principal, P= Rs. 80,000
Rate of interest, r=5%
And we have to find the amount at the end of three year so t=3.
The amount credited at the end of the third year, $A = P{\left[ {1 + \dfrac{r}{{100}}} \right]^t}$
$A = 80000{\left( {1 + \dfrac{5}{{100}}} \right)^3} = 80000 \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} \times \dfrac{{21}}{{20}} = 92610$.
Interest of third year=Amount of three years-Amount of two years.
Interest=92610-88200 (as we find the amount for two years above).
=4410
$\therefore $ The interest for the third year is 44410. Answer
Note: Whenever we face such a type of question the key concept for solving the question is you must always remember the formula related to compound interest for solving such a type of question. By putting the given terms in formula you can easily get the answer. And for finding the interest for a specific year just subtract the amount of its previous year from the amount of that year.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Express the following as a fraction and simplify a class 7 maths CBSE

The length and width of a rectangle are in ratio of class 7 maths CBSE

The ratio of the income to the expenditure of a family class 7 maths CBSE

How do you write 025 million in scientific notatio class 7 maths CBSE

How do you convert 295 meters per second to kilometers class 7 maths CBSE

Trending doubts
When people say No pun intended what does that mea class 8 english CBSE

How many ounces are in 500 mL class 8 maths CBSE

In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

Which king started the organization of the Kumbh fair class 8 social science CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Advantages and disadvantages of science
