Question

Manoj has a metal block of dimensions of \[25cm\times 10cm\times 5cm\]. Now the mass of the block is $5 \mathrm{~kg}$. Then calculate the greatest and least pressure exerted by the block when kept on the ground in different positions?

Answer 1

Hint: Pressure is characterized as the actual force applied on an item. The force applied is perpendicular to the outside of articles per unit region. The essential formula for pressure is F/A (Force per unit area). Unit of pressure is Pascals (Pa). Sorts of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.

Complete step by step answer:
The mass of the block is $M=5~{kg}$
We know,$F={Mg}$
Where F is force
And g is the acceleration due to gravity
$\Rightarrow 5\times 9.8$
$\Rightarrow 49~{N}$
Lowest pressure can be calculated by the following method:
The area A is calculated as,
$\Rightarrow A=25\times 10$
$\Rightarrow 250~{c}{{{m}}^{2}}=0.025{{m}^{2}}$
The pressure P is calculated as,
$\Rightarrow P=\dfrac{F}{A}$
$\Rightarrow \dfrac{49000}{0.025}=1960k{g}/{{{m}}^{2}}$
Greatest pressure can be calculated by the following method:
The area A can be calculated as,
$\Rightarrow A=10\times 5$
$\Rightarrow 50~{c}{{{m}}^{2}}=0.005{{m}^{2}}$
The pressure P can be calculated as,
$\Rightarrow P=\dfrac{F}{A}$
$\Rightarrow \dfrac{49000}{0.005}=9800k{g}/{{{m}}^{2}}$

Therefore, the greatest pressure calculated is $9800k{g}/{{{m}}^{2}}$ and the lowest pressure calculated is $1960k{g}/{{{m}}^{2}}$.

Note: We know that the formula for pressure is P=F/A. The force can be calculated by multiplying mass with acceleration due to gravity. Then, area can be calculated and put into the formula for pressure. We can describe pressure with an example such that, on the off chance that you attempted to pound a bowling pin into the wall, nothing would most likely occur aside from individuals choosing to not lend you their bowling pins. Be that as it may, in the event that you hammer with a similar power on a nail, the nail would be significantly bound to enter the wall.