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# Manju’s weight is 14% more than Anju’s weight. If Anju’s weight is 63 kg, find Manju’s weight.

Last updated date: 21st Jun 2024
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If a number y is m% greater than the number x then we can say that $y=x\left( 1+\dfrac{m}{100} \right)$.
So, Manju’s weight will be $63\left( 1+\dfrac{14}{100} \right)=\dfrac{63\times 114}{100}=71.82$ kg.
Note: We also could have used a variable as the weight of Manju. Let that be p. We find that Manju’s weight is $\left( p-63 \right)$ kg greater than Anju’s weight. Now we find the percentage which is $\dfrac{\left( p-63 \right)}{63}\times 100$ and that will be equal to 14. So, the equation becomes $\dfrac{\left( p-63 \right)}{63}\times 100=14$. We solve the equation to get the value of p. We also can use the concept of 100 to find that with respect to that age of Anju, Manju’s weight will be $100+14=114$. So, for Anju’s weight of 63 kg, Manju’s weight will be $\dfrac{63\times 114}{100}=71.82$.