Question

Loss of beta particle is equivalent to:
A) Increase of one neutron only
B) Decrease of one neutron only
C) Both (a) and (b)
D) None of these

Answer 1

Hint: We have to know that nuclear chemistry is one of the important parts of chemistry. Radioactivity is nothing but the phenomenon of spontaneous disintegration of atomic nuclei, resulting in the form of emission of radioactive rays called radioactivity. This kind of radioactivity was developed from the nucleus of the atom. Hence, this radioactivity is important for nuclear chemistry. Nuclear chemistry was first discovered by Henry Becqurel.

Complete answer:
We must remember that the protons, neutrons, helium or alpha particles, electron or beta particles, deuterons and positrons are used as projectile and ejected particles in nuclear chemistry.
The electron or beta particle is nothing but only one electron in the particles. The symbol of an electron or beta particle is ${}_{-1}^{0}e$.
Loss of beta particles is equivalent to loss of electrons in nuclear reaction.
Hence, Loss of a beta particle is equivalent to loss of one electron.

So, option D is correct. Because no one matches the above statement.

Note:
As we know that the projectiles and ejectiles are an important part of nuclear chemistry. The projectile is nothing but the particle used to bombard the parent or target nucleus in the nuclear reaction. In nuclear reaction, the product side except daughter nucleus and other particles are considered as ejected particles. The proton is nothing but only one proton in the particles. The symbol of protons is ${}_{1}^{1}H$ .The neutrons are nothing but only one neutron in the particles. The symbol of a neutron is ${}_{0}^{1}n$ .The helium or alpha particle is nothing but only one helium in the particles. The symbol of a helium or alpha particle is ${}_{2}^{4}He$.The deuteron is nothing but one neutron and one proton in the particles. The symbol of deuteron is ${}_{1}^{2}H$ .The positron is nothing but only one positron in the particles. The symbol of positron is ${}_{+1}^{0}e$.