
Look at several examples of rational numbers in the form \[\dfrac{p}{q},q \ne 0\], where \[p\] and \[q\] are integers with no common factors other than 1 and having terminating decimal representations (expansions). Can you guess what property \[q\] must satisfy?
Answer
511.5k+ views
Hint: We will first consider the given statement in the question that is the rational numbers of the form \[\dfrac{p}{q},q \ne 0\], where \[p\] and \[q\] are integers with no common factors other than 1 and having terminating decimal representations. As we have to find the property that \[q\] must satisfy, we know that there is no common factor other than 1 which means there is no other number which will divide both \[p\] and \[q\] and also maintain the decimal representation implies that prime factorization of \[q\] has only powers of 2 or power of 5 or both and this will give us the required property that \[q\] will satisfy.
Complete step-by-step answer:
We will first consider the given statement that is the rational numbers of the form \[\dfrac{p}{q},q \ne 0\], where \[p\] and \[q\] are integers with no common factors other than 1 implies that there will no common divisor between \[p\] and \[q\] other than 1 which will divide both the integers.
Also, it is given that the rational numbers in the form \[\dfrac{p}{q},q \ne 0\] have the terminating decimal expansion which means that the number will terminate after some time and there is no pattern which will be repeated.
We need to find the property where \[q\] must satisfy the above statements.
Thus, we get that the property that \[q\] must satisfy in order that the rational numbers of the form \[\dfrac{p}{q},q \ne 0\], with no common factor other than 1, have maintaining decimal representation is prime factorization of \[q\] has only powers of 2 or power of 5 or both.
That is, we get,
\[{2^m} \times {5^n}\] where \[m = 1,2,3...\] or \[n = 1,2,3...\].
Here, we can consider one example such as \[\dfrac{1}{4},\dfrac{{37}}{{25}},\dfrac{{17}}{{20}}\] which has terminating decimal expansion.
Thus, we get,
\[\dfrac{1}{4} = \dfrac{1}{{2 \times 2 \times 1}}\] , \[\dfrac{{37}}{{25}} = \dfrac{{37 \times 1}}{{5 \times 5 \times 1}}\] and \[\dfrac{{17}}{{20}} = \dfrac{{17 \times 1}}{{2 \times 2 \times 5 \times 1}}\]
Hence, we can see that the denominator is either power of 2 or power of 5 or both.
Thus, we can conclude that in the rational number of the form \[\dfrac{p}{q}\], \[q\] is either power of 2 or power of 5 or both.
Note: Considering an example in such questions makes the concept clearer. We have to consider only those integers of the form of rational numbers which are terminating that is no pattern is followed or repeated after dividing the number gets terminated.
Complete step-by-step answer:
We will first consider the given statement that is the rational numbers of the form \[\dfrac{p}{q},q \ne 0\], where \[p\] and \[q\] are integers with no common factors other than 1 implies that there will no common divisor between \[p\] and \[q\] other than 1 which will divide both the integers.
Also, it is given that the rational numbers in the form \[\dfrac{p}{q},q \ne 0\] have the terminating decimal expansion which means that the number will terminate after some time and there is no pattern which will be repeated.
We need to find the property where \[q\] must satisfy the above statements.
Thus, we get that the property that \[q\] must satisfy in order that the rational numbers of the form \[\dfrac{p}{q},q \ne 0\], with no common factor other than 1, have maintaining decimal representation is prime factorization of \[q\] has only powers of 2 or power of 5 or both.
That is, we get,
\[{2^m} \times {5^n}\] where \[m = 1,2,3...\] or \[n = 1,2,3...\].
Here, we can consider one example such as \[\dfrac{1}{4},\dfrac{{37}}{{25}},\dfrac{{17}}{{20}}\] which has terminating decimal expansion.
Thus, we get,
\[\dfrac{1}{4} = \dfrac{1}{{2 \times 2 \times 1}}\] , \[\dfrac{{37}}{{25}} = \dfrac{{37 \times 1}}{{5 \times 5 \times 1}}\] and \[\dfrac{{17}}{{20}} = \dfrac{{17 \times 1}}{{2 \times 2 \times 5 \times 1}}\]
Hence, we can see that the denominator is either power of 2 or power of 5 or both.
Thus, we can conclude that in the rational number of the form \[\dfrac{p}{q}\], \[q\] is either power of 2 or power of 5 or both.
Note: Considering an example in such questions makes the concept clearer. We have to consider only those integers of the form of rational numbers which are terminating that is no pattern is followed or repeated after dividing the number gets terminated.
Recently Updated Pages
Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

How many ounces are in 500 mL class 8 maths CBSE

How many ten lakhs are in one crore-class-8-maths-CBSE

Name the states through which the Tropic of Cancer class 8 social science CBSE

Explain land use pattern in India and why has the land class 8 social science CBSE

One cusec is equal to how many liters class 8 maths CBSE
