Question

How long is 33 inches added to 4 feet and 7 inches?

Answer 1

Hint: In the given question, we have been given two units of measurements – one containing just inches and one containing feet and inches. We have to add them both. To do that, we are going to add the two inches together. If we get a sum bigger than or equal to one foot (i.e., 12 inches), then we convert it to feet and add it to the second measurement’s feet.

Formula Used:
For solving this question, we are going to use the following relation between feet and inches:
\[1ft = 12in\]

Complete step-by-step answer:
We have to add \[33in\] and \[4ft7in\].
For that, we are first going to add just the two inches,
\[33 + 7 = 40in > 12in\]
Now, we are going to convert \[40in\] to feet; divide \[40\] by \[12\] – the quotient gives the feet and the remainder (if any) is the remaining inches.
\[12\mathop{\left){\vphantom{1\begin{array}{l}{\rm{ }}40\\\dfrac{{36}}{{\dfrac{{04}}{{}}}}\end{array}}}\right.
\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{array}{l}{\rm{ }}40\\\dfrac{{36}}{{\dfrac{{04}}{{}}}}\end{array}}}}
\limits^{\displaystyle\,\,\, 3}\]
Hence, \[40in = 3ft4in\]
Hence, \[4ft7in + 33in = 4ft + 3ft4in = 7ft4in\]

Note: In the given question, we had to solve for the value of sum of two lengths in different units, both of which are not imperial units of measurement. To do that, we add the measurement in the larger measurement and the one to be added, and convert them to the larger together, and then take the carry over to the larger measurement.