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# List the factors on which the strength of magnetic field produced by(A) A current carrying straight conductor(B) Current carrying solenoid depends.

Last updated date: 19th Sep 2024
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Hint For a current carrying conductor, the magnetic field is directly proportional to the current and inversely proportional to the distance from the conductor. For the solenoid, it is directly proportional to the current and number of turns per unit length of the solenoid.
Formula used: In this solution we will be using the following formula;
$\Rightarrow B = \dfrac{{\mu I}}{{2\pi r}}$ where $B$ is the magnetic field or magnetic flux density produces by a current carrying straight conductor,$\mu$is the permeability of free space, $I$ is the current flowing through a straight conductor and $r$ is the distance from the wire considered.
$\Rightarrow B = \mu nI$ where $B$, in this case, is the magnetic field within the turns of a solenoid, $n$ is the number of turns per unit length made by the solenoid, and $I$ is the current flowing through the solenoid.

$\Rightarrow B = \dfrac{{\mu I}}{{2\pi r}}$ where $\mu$ is the permeability of free space, $I$ is the current flowing through a straight conductor and $r$ is the distance from the wire considered.
$\Rightarrow B = \mu nI$ where ,$n$ is the number of turns per unit length made by the solenoid.