
List price of scooter is Rs. 35000. It is available at a discount of 8%. Find the selling price of the scooter.
Answer
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Hint: We will first calculate the discount we have on the listed price of the scooter to get the discount obtained on the scooter. Now, we will subtract the discount from the listed price and thus we have the required answer.
Complete step-by-step solution:
Since we are given that the listed price of the scooter is Rs. 35000. ……………..(1)
We are also given that the scooter is available at a discount of 8%.
We will now use the following formula:-
$ \Rightarrow $Discount = $\dfrac{{Discount\% }}{{100}} \times L.P.$ , where L.P. is the listed price.
So, discount at the scooter = 8% of the listed price.
$ \Rightarrow $Discount = $Rs.\dfrac{8}{{100}} \times 35000$
Simplifying the calculations on the RHS, we will obtain:-
$ \Rightarrow $Discount = $Rs.\left( {8 \times 350} \right)$
Simplifying the calculations on the RHS a bit further, we will obtain:-
$ \Rightarrow $Discount = $Rs.2800$ …………..(2)
Now, we will use the formula given by the following expression:-
$ \Rightarrow $Selling Price = Listed Price – Discount
Putting the values in the above expression using the equations (1) and (2), we will then obtain:-
$ \Rightarrow $Selling Price = Rs. (35000 – 2800)
Simplifying the calculations on the RHS, we will obtain:-
$ \Rightarrow $Selling Price = Rs. 32200
$\therefore $ The selling price of the scooter is Rs. 32200.
Note: The students must commit to memory the following formulas:-
$ \Rightarrow $Discount = $\dfrac{{Discount\% }}{{100}} \times L.P.$ , where L.P. is the listed price.
$ \Rightarrow $Selling Price = Listed Price – Discount
The students must not try to memorize the formula, it will be easy to remember if they apply it on themselves like if they see anything in the shop or the store which is listed for Rs. 100 and we are given a discount of 10% on it, we will definitely get some discount on the listed price and we will have to pay 10% of 100 less than we had to. Therefore, these both the formulas are derived.
Complete step-by-step solution:
Since we are given that the listed price of the scooter is Rs. 35000. ……………..(1)
We are also given that the scooter is available at a discount of 8%.
We will now use the following formula:-
$ \Rightarrow $Discount = $\dfrac{{Discount\% }}{{100}} \times L.P.$ , where L.P. is the listed price.
So, discount at the scooter = 8% of the listed price.
$ \Rightarrow $Discount = $Rs.\dfrac{8}{{100}} \times 35000$
Simplifying the calculations on the RHS, we will obtain:-
$ \Rightarrow $Discount = $Rs.\left( {8 \times 350} \right)$
Simplifying the calculations on the RHS a bit further, we will obtain:-
$ \Rightarrow $Discount = $Rs.2800$ …………..(2)
Now, we will use the formula given by the following expression:-
$ \Rightarrow $Selling Price = Listed Price – Discount
Putting the values in the above expression using the equations (1) and (2), we will then obtain:-
$ \Rightarrow $Selling Price = Rs. (35000 – 2800)
Simplifying the calculations on the RHS, we will obtain:-
$ \Rightarrow $Selling Price = Rs. 32200
$\therefore $ The selling price of the scooter is Rs. 32200.
Note: The students must commit to memory the following formulas:-
$ \Rightarrow $Discount = $\dfrac{{Discount\% }}{{100}} \times L.P.$ , where L.P. is the listed price.
$ \Rightarrow $Selling Price = Listed Price – Discount
The students must not try to memorize the formula, it will be easy to remember if they apply it on themselves like if they see anything in the shop or the store which is listed for Rs. 100 and we are given a discount of 10% on it, we will definitely get some discount on the listed price and we will have to pay 10% of 100 less than we had to. Therefore, these both the formulas are derived.
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