Question

What is the Lewis formula for carbon oxy-sulphide $ \left( COS \right) $ ?

Answer 1

Hint :We know that for solving this problem, you should have the knowledge about polyatomic ion and oxidation number. Polyatomic ion is an ion containing more than one atom.Oxidation number is the number of electrons lost or gained by an element during a reaction.

Complete Step By Step Answer:
Lewis structure helps in representing valence electrons of a molecule. On calculating the formal
Charges with respect to the Lewis structure, the charge on a polyatomic ion can be identified easily. Let's first try to draw the Lewis structure of trichloride. It has three chlorine atoms and only one boron so boron will be a central atom in this molecular structure.
Step-1: To solve the given problem, let’s determine the valence electron of all the atoms present in the compound.

Step-2: Here, the compound is Carbon Oxy Sulphide. Here, Carbon has $ 4 $ valence electron, Oxygen contains
 $ 6 $ valence electron and sulphur also contains $ 6 $ valence electron.
Step-3: If we look closely the formula can have the same Lewis structure as that of $ C{{O}_{2}} $ . Here carbon have $ 4 $ valence electron and $ 2 $ Oxygen atoms have $ 6 $ valence electron which can be compared with
 $ 1 $ Oxygen valence and $ 1 $ Sulphur valence of $ COS. $
So, keeping the structure of COS similar to $ C{{O}_{2}} $ and replacing $ 1 $ Oxygen to Sulphur we get the
answer.

Note :
Remember that while determining the Lewis structure of a compound, the valence electron should be remembered and determined correctly so as to avoid any mistakes and if possible the Lewis structures of some basic compounds can be learned to simplify the process. VSEPR is valence shell electron pair repulsion, it simply tells us that nonbonding and bonding electron pairs of the central atom in a molecule push each other away.