What is the Lewis electron dot structure of the ion compound molecule Boron nitride?
Answer
552.6k+ views
Hint: Lewis electron dot structure is used to represent the number of valence electrons in an atom or type of bonding that exists between atoms of a molecule. The valence electrons are represented by dots on a symbol of respective element and combine with the valence electron of another element to form a chemical bond.
Complete answer:
To find the Lewis electron dot structure of Boron Nitride, we need to follow certain steps:
Step1: Finding the formula of the given compound.
Boron Nitride is a compound consisting of Boron and Nitrogen. The type of bonding between boron and nitrogen is covalent bonding and it exists in various crystalline forms similar to that of carbon. The chemical formula of Boron Nitride is $BN$ .
Step2: Sketching electron dot diagram of Boron.
Atomic number of boron $ = 5$
Electronic configuration $ = 1{s^2}2{s^2}2{p^1}$
The outermost shell of boron consists of $2s$ and $2p$ orbitals. Hence there are $3$ valence electrons in boron atoms.
Therefore, electron dot structure of boron can be represented as:
Step3: Sketching electron dot diagram of Nitrogen.
Atomic number of Nitrogen $ = 7$
Electronic configuration $ = 1{s^2}2{s^2}2{p^3}$
The outermost shell of boron consists of $2s$ and $2p$ orbitals. Hence there are $5$ valence electrons in Nitrogen atoms.
Therefore, electron dot structure of Nitrogen can be represented as:
Step4: Finding Lewis electron dot structure of Boron nitride.
Valence electrons of boron make bonds with valence electrons of Nitrogen atoms and remaining electrons on any element after bonding are considered as lone pairs of electrons.
Hence electron dot structure of Boron Nitride is as follows:
Note:
The electronic configuration of each atom should be done according to Aufbau Principle and Hund’s Rule. To clear the difference between valence electrons of nitrogen and boron, the valence electrons of boron are represented as circles whereas valence electrons of nitrogen atoms are represented as disc.
Complete answer:
To find the Lewis electron dot structure of Boron Nitride, we need to follow certain steps:
Step1: Finding the formula of the given compound.
Boron Nitride is a compound consisting of Boron and Nitrogen. The type of bonding between boron and nitrogen is covalent bonding and it exists in various crystalline forms similar to that of carbon. The chemical formula of Boron Nitride is $BN$ .
Step2: Sketching electron dot diagram of Boron.
Atomic number of boron $ = 5$
Electronic configuration $ = 1{s^2}2{s^2}2{p^1}$
The outermost shell of boron consists of $2s$ and $2p$ orbitals. Hence there are $3$ valence electrons in boron atoms.
Therefore, electron dot structure of boron can be represented as:
Step3: Sketching electron dot diagram of Nitrogen.
Atomic number of Nitrogen $ = 7$
Electronic configuration $ = 1{s^2}2{s^2}2{p^3}$
The outermost shell of boron consists of $2s$ and $2p$ orbitals. Hence there are $5$ valence electrons in Nitrogen atoms.
Therefore, electron dot structure of Nitrogen can be represented as:
Step4: Finding Lewis electron dot structure of Boron nitride.
Valence electrons of boron make bonds with valence electrons of Nitrogen atoms and remaining electrons on any element after bonding are considered as lone pairs of electrons.
Hence electron dot structure of Boron Nitride is as follows:
Note:
The electronic configuration of each atom should be done according to Aufbau Principle and Hund’s Rule. To clear the difference between valence electrons of nitrogen and boron, the valence electrons of boron are represented as circles whereas valence electrons of nitrogen atoms are represented as disc.
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