
Let $f:R \to R$ be defined by $f\left( x \right) = \left\{ \begin{gathered}
2x{\text{ }}x > 3 \\
{x^2}{\text{ }}1 < x \leqslant 3 \\
3x{\text{ }}x \leqslant 1 \\
\end{gathered} \right\}$. Then what is the value of $f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right)$?
$
{\text{A}}{\text{. 9}} \\
{\text{B}}{\text{. 14}} \\
{\text{C}}{\text{. 5}} \\
{\text{D}}{\text{. 10}} \\
$
Answer
588k+ views
Hint- Here, we will proceed by finding the values of the function for some specific values of x (in this case, we will find the values of the function corresponding to x = -1, x = 2 and x = 4) according to the definition of the function given.
Complete step-by-step answer:
The given function is defined as $f\left( x \right) = \left\{ \begin{gathered}
2x{\text{ }}x > 3 \\
{x^2}{\text{ }}1 < x \leqslant 3 \\
3x{\text{ }}x \leqslant 1 \\
\end{gathered} \right\}$
In $f\left( { - 1} \right)$, x = -1 which lies in the interval $x \leqslant 1$ and for this interval the function is defined as $f\left( x \right) = 3x$
By putting x = -1 in the above function, we get
$
f\left( { - 1} \right) = 3\left( { - 1} \right) \\
\Rightarrow f\left( { - 1} \right) = - 3{\text{ }} \to {\text{(1)}} \\
$
In $f\left( 2 \right)$, x = 2 which lies in the interval $1 < x \leqslant 3$ and for this interval the function is defined as $f\left( x \right) = {x^2}$
By putting x = 2 in the above function, we get
$
f\left( 2 \right) = {2^2} \\
\Rightarrow f\left( 2 \right) = 4{\text{ }} \to {\text{(2)}} \\
$
In $f\left( 4 \right)$, x = 4 which lies in the interval $x > 3$ and for this interval the function is defined as $f\left( x \right) = 2x$
By putting x = 4 in the above function, we get
$
f\left( 4 \right) = 2 \times 4 \\
\Rightarrow f\left( 4 \right) = 8{\text{ }} \to {\text{(3)}} \\
$
The value of the expression $f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right)$ can be obtained by using equation
$
f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right) = - 3 + 4 + 8 \\
\Rightarrow f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right) = 9 \\
$
Therefore, the value of $f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right)$ is 9.
Hence, option A is correct.
Note- In this particular problem, the given function has three different definitions according to the three intervals. Here, the value of the function for any specific value of x can be calculated by considering the corresponding definition of the function and then substituting that particular value of the variable x.
Complete step-by-step answer:
The given function is defined as $f\left( x \right) = \left\{ \begin{gathered}
2x{\text{ }}x > 3 \\
{x^2}{\text{ }}1 < x \leqslant 3 \\
3x{\text{ }}x \leqslant 1 \\
\end{gathered} \right\}$
In $f\left( { - 1} \right)$, x = -1 which lies in the interval $x \leqslant 1$ and for this interval the function is defined as $f\left( x \right) = 3x$
By putting x = -1 in the above function, we get
$
f\left( { - 1} \right) = 3\left( { - 1} \right) \\
\Rightarrow f\left( { - 1} \right) = - 3{\text{ }} \to {\text{(1)}} \\
$
In $f\left( 2 \right)$, x = 2 which lies in the interval $1 < x \leqslant 3$ and for this interval the function is defined as $f\left( x \right) = {x^2}$
By putting x = 2 in the above function, we get
$
f\left( 2 \right) = {2^2} \\
\Rightarrow f\left( 2 \right) = 4{\text{ }} \to {\text{(2)}} \\
$
In $f\left( 4 \right)$, x = 4 which lies in the interval $x > 3$ and for this interval the function is defined as $f\left( x \right) = 2x$
By putting x = 4 in the above function, we get
$
f\left( 4 \right) = 2 \times 4 \\
\Rightarrow f\left( 4 \right) = 8{\text{ }} \to {\text{(3)}} \\
$
The value of the expression $f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right)$ can be obtained by using equation
$
f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right) = - 3 + 4 + 8 \\
\Rightarrow f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right) = 9 \\
$
Therefore, the value of $f\left( { - 1} \right) + f\left( 2 \right) + f\left( 4 \right)$ is 9.
Hence, option A is correct.
Note- In this particular problem, the given function has three different definitions according to the three intervals. Here, the value of the function for any specific value of x can be calculated by considering the corresponding definition of the function and then substituting that particular value of the variable x.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

How many 5 digit telephone numbers can be constructed class 11 maths CBSE

Draw a well labelled diagram of reflex arc and explain class 11 biology CBSE

What is the difference between noise and music Can class 11 physics CBSE

Trending doubts
In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Write the differences between monocot plants and dicot class 11 biology CBSE

